What is the 15th term in the pattern with the formula 10n

svetlana [45]

The correct answer is:

pairs 1 and 3

Explanation:

Congruent figures are the same size and the same shape.

Pair 1 has two polygons that are the same size and same shape; they are congruent.

Pair 2 has two polygons that are not the same size; the "stick" of the t shape of one figure is longer than the "stick" of the second figure.

Pair 3 has two polygons that are the same size and same shape; they are congruent.

Pair 4 has two polygons that are the same shape, but the first figure in green is larger than the second shape in red; this means they are not congruent.

3 0

3 years ago

Read 2 more answers

at 4 a.m. the outside temperature was -28 Fahrenheit by 4 p.m. it was Rose 38 degrees what was the temperature at 4 p.m.

vaieri [72.5K]

Answer:

10 degrees f

Step-by-step explanation:

-28+38=10

5 0

3 years ago

Read 2 more answers

BRAINLIEST ✨

inna [77]

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6Common ratio: 4/(8/3) = 3/2 same as 6/4 = 3/2. Correct.

Step-by-step explanation:

Am I right? just commet if I'm wrong

then TANKYOU>^_^<!

7 0

3 years ago

Please please please help me out

NemiM [27]

Answer:

youre welcome for the answer

Step-by-step explanation:

5 0

3 years ago

Complete the function table and write the function rule

Andrej [43]

Answer:

6 and -22

Step-by-step explanation:

See attached image.

3 0

2 years ago

What is the 15th term in the pattern with the formula 10n – 5?