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olasank [31]
2 years ago
9

A soccer ball has an interior

Mathematics
2 answers:
iVinArrow [24]2 years ago
6 0
<h2>Answer:</h2>

<u>Volume of soccer ball = 4/3πr³</u>

[Plug the value of r = d/2]

Now, <u>Volume = 4/3π(d/2)³</u>

<u>Volume = 4/3πd³/8</u>

= πd³/6

= 22 × 22³/7 × 6

= 234256/42

= <u>5,577.5cm³ or 5578cm³ approx</u>.

AnnZ [28]2 years ago
4 0

Answer:

5575 cm³

Step-by-step explanation:

The volume of a sphere is V = (4/3)πr³.  If we substitute r = (d/2 where r is the radius and d the diameter), this formula becomes:

                                        πd³

V = (4/3)π·d³/8, or V = -------------

                                           6

and so, if d = 22 cm, the volume is:

        π(22 cm)³

V = ------------------- = 5575 cm³

              6

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Suppose the manager of a gas station monitors how many bags of ice he sells daily along with recording the highest temperature e
Maslowich

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Equation of regression line :

Yˆ = −114.05+2.17X

X = Temperature in degrees Fahrenheit (°F)

Y = Number of bags of ice sold

On one of the observed days, the temperature was 82 °F and 66 bags of ice were sold.

X = 82°F ; Y = 66 bags of ice sold

1. Determine the number of bags of ice predicted to be sold by the LSR line, Yˆ, when the temperature is 82 °F.

X = 82°F

Yˆ = −114.05+2.17(82)

Y = - 114.05 + 177.94

Y = 63.89

Y = 64 bags

2. Compute the residual at this temperature.

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4 0
2 years ago
7.50x +4.50y = 2,212.5<br> x+y = 375
AURORKA [14]

Answer:

5x+3y-1475=0

Step-by-step explanation:

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3 0
2 years ago
Steven lives 1500 yards from the corner store, and 2700 yards from the park. the park, the store, and steves house are all colli
Alexandra [31]

Answer:

4200

Step-by-step explanation:

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8 0
1 year ago
A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele
aev [14]

THIS IS THE COMPLETE QUESTION

basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Yes, exactly 0.6 seconds after the shot is launched.

Yes, between 0.64 seconds and 0.65 seconds after the shot is launched

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

No, the shot is not blocked.

Answer:

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Given that the

equation for shot block height h = 9 + 25t – 16t2.

equation for ball height h = 6 + 30t – 16t2.

From the question ,it can be deducted that the shot is made before two tenths of a second or 0.2seconds

CHECK THE ATTACHMENT TO COMPLETE THE DETAILED SOLUTION

5 0
3 years ago
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