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3 years ago

A soccer ball has an interior

Mathematics

2 answers:

iVinArrow [24]3 years ago

6 0

<h2>Answer:</h2>

<u>Volume of soccer ball = 4/3πr³</u>

[Plug the value of r = d/2]

Now, <u>Volume = 4/3π(d/2)³</u>

<u>Volume = 4/3πd³/8</u>

= πd³/6

= 22 × 22³/7 × 6

= 234256/42

= <u>5,577.5cm³ or 5578cm³ approx</u>.

AnnZ [28]3 years ago

4 0

Answer:

5575 cm³

Step-by-step explanation:

The volume of a sphere is V = (4/3)πr³. If we substitute r = (d/2 where r is the radius and d the diameter), this formula becomes:

πd³

V = (4/3)π·d³/8, or V = -------------

and so, if d = 22 cm, the volume is:

π(22 cm)³

V = ------------------- = 5575 cm³

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Please answer this correctly which is the correct options

MakcuM [25]

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3 years ago

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Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

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Once

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We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

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3 years ago

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Mashcka [7]

<h3>Answer:</h3>

5 units

<h3>Step-by-step explanation:</h3>

A point 4 up and 3 over from its original location has moved a distance that can be found using the Pythagorean theorem.

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... d = √25 = 5 . . . . units

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago