3 years ago

The circumference of a circle is like the ________ of a figure.

Mathematics

2 answers:

adelina 88 [10]3 years ago

8 0

Answer:

The answer would be 'B. perimeter'.

Nina [5.8K]3 years ago

5 0

The guy above me is right.

You might be interested in

What 124.2÷9 step-by-step explanation please help !! ( long division ..”

Andre45 [30]

Answer: 13.8

Step-by-step explanation:

5 0

3 years ago

What is the solution set for the given inequality if the replacement set for r is {5, 6, 7, 8, 9, 10}? 2r ≤ 3r – 8 A. {8, 9, 10}

TiliK225 [7]

$2r\leq3r-8\\
r\geq8\\\Downarrow\\
\boxed{\{8,9,10\}}$

8 0

3 years ago

If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers

seraphim [82]

Answer:

a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

$\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}$

<h2>Simplify it in steps:</h2>

Bring both fractions into common denominator:

$\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}$

Simplify:

$\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =$

$\dfrac{4\sqrt{14} }{7-4} =$

$\dfrac{4}{3} \sqrt{14} }$

Compare the result with given expression to get:

a = 4/3 and b = 0

4 0

2 years ago

There are 970 students in bayton high school. Brian takes a random sample of 100 students. He asks these 100 students which subj

Pani-rosa [81]

Answer:

How to do the estimation

Step-by-step explanation:

He can use the probability of how many people chose English and multiply by 9.7 since there are 970 people / 100 people who asked = 9.7

7 0

3 years ago

Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solut

givi [52]

10%=30 15%=20 I hope this helps <3

3 0

3 years ago