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timama [110]
3 years ago
8

%7D%20%7D%7B3%20%7D%20" id="TexFormula1" title=" {3}^{x ^{2 - 1} } = \frac{ {27}^{ - x} }{3 } " alt=" {3}^{x ^{2 - 1} } = \frac{ {27}^{ - x} }{3 } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
vitfil [10]3 years ago
4 0

Answer:

-1/4

Step-by-step explanation:

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What is the average rate of change of the function in the table at the interval x = -1 to x = 1?
Andre45 [30]

Answer:

the answer is undefined

Step-by-step explanation:

If a function, f(x), is continuous (that is, has values for every x in the interval) from x=- 1 to x=1 ), then the average rate of change is:( total amount that f(x) changes ) / (total amount that x changes)( f(1) - f(-1) ) / ( (1) - (-1) )( f(1) - f(-1) ) / 2The variable x changes from (-1) to (1). That value is 2. [note: (1)-(-1) ]The function changes from f(-1) to f(1). You must determine f(1)-f(-1) and use that value as the numerator.Fill in the values to determine the average rate of change: ( f(1) - f(-1) ) / 2However, if the plot of y values is not a function, and there is some x value between -1 and 1 for which f(x) is undefined, then the rate of change of y from f(-1) to f(1) is also undefined.

4 0
2 years ago
Helpp please :)) Explain how you got the answer too, so I understand how to solve.
Lana71 [14]
4 by x is the answer
8 0
2 years ago
Esther estimates that she will need about $8,600 for he first year of 11 point
Elena-2011 [213]

Answer:

$129

Step-by-step explanation:

Esther estimates that she will need about $8,600 for he first year of 11 point

tuition at college. Her grandparents contribution will cover 50% of the

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4 0
3 years ago
Read 2 more answers
The terms in the sequence decrease by the same amount each time:
luda_lava [24]

Answer:the nth term of the sequence, Tn= -3n +12

Step-by-step explanation:

The nth term of an arithmetic progression is given as

Tn=  a+ (n-1) d

where a= first term

and d = common difference

In this sequence, 9, 6 ,3 ,0, -3, -6 we can see that  the number is decreasing by 3

The first term, a= 9

and common difference, d = -3

using our formulae

Tn=  a+ (n-1) d

Tn= 9 + ( n-1) -3

Tn=9- 3n+ 3

Tn= -3n +12

7 0
3 years ago
James can jog twice as fast as he can walk. He was able to jog the first 9 miles to his grandmother’s house, but then he tired a
dimulka [17.4K]

Answer:

6 mile/hour

Explanation :



Let the speed of walking of James = x mile/hour


speed of jogging = 2x mile/hour


9/2x + 1.5/x = 2


= > (9 + 3)/2x = 2


= > 12 = 4x


= > x = 3


Average speed of walking = 3 mile/hour


Average speed of jogging = 2 * 3 = 6 mile/hour

5 0
3 years ago
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