PLEASE HELP!!! 50 POINTS!! WILL GIVE BRAINLIEST!!!
1 answer:
Answer:
208.8 mi
Step-by-step explanation:
Form a triangle with the centre of the Earth (C) at one point, the horizon (H) as a second point, and the top of Mt. Everest (O) as the third (see diagram).
Let
r = Earth’s radius
h = height of Mt Everest
d = distance to horizon
∆CHO is a right triangle.
d² + r² = (r+h)²
d² + 3959² = (3959+5.5)²
d² + 15 673 681 = 3964.5²
d² + 15 673 681 = 15 717 260 Subtract 15 673 681 from each side
d² = 43 579 Take the square root of each side
d = 208.8 mi
The distance from the top of Mt Everest to the horizon is 208.8 mi.
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Answer: The equation is y = 4x+3
Slope = 4
y intercept = 3
========================================================
Explanation:
Let's start off by finding the slope.
The slope is 4.
The y intercept is 3 because of the point (0,3)
We go from y = mx+b to y = 4x+3
m = slope
b = y intercept
---------------
Check:
Plug in x = 0 and we should get to y = 3
y = 4x+3
y = 4(0)+3
y = 0+3
y = 3
That works out. Now try x = 4. It should lead to y = 19
y = 4x+3
y = 4(4)+3
y = 16+3
y = 19
The answer is confirmed.