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iragen [17]
3 years ago
7

PLEASE HELP!!! 50 POINTS!! WILL GIVE BRAINLIEST!!!

Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

208.8 mi

Step-by-step explanation:

Form a triangle with the centre of the Earth (C) at one point, the horizon (H) as a second point, and the top of Mt. Everest (O) as the third (see diagram).

Let

r  = Earth’s radius

h = height of Mt Everest

d = distance to horizon

∆CHO is a right triangle.

               d² + r² = (r+h)²

       d² + 3959² = (3959+5.5)²

d² + 15 673 681 = 3964.5²

d² + 15 673 681 = 15 717 260     Subtract 15 673 681 from each side

                     d² = 43 579             Take the square root of each side

                      d = 208.8 mi

The distance from the top of Mt Everest to the horizon is 208.8 mi.

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Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

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Step-by-step explanation:

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f(x) = x² + 3·x + 2

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