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iragen [17]
3 years ago
7

PLEASE HELP!!! 50 POINTS!! WILL GIVE BRAINLIEST!!!

Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

208.8 mi

Step-by-step explanation:

Form a triangle with the centre of the Earth (C) at one point, the horizon (H) as a second point, and the top of Mt. Everest (O) as the third (see diagram).

Let

r  = Earth’s radius

h = height of Mt Everest

d = distance to horizon

∆CHO is a right triangle.

               d² + r² = (r+h)²

       d² + 3959² = (3959+5.5)²

d² + 15 673 681 = 3964.5²

d² + 15 673 681 = 15 717 260     Subtract 15 673 681 from each side

                     d² = 43 579             Take the square root of each side

                      d = 208.8 mi

The distance from the top of Mt Everest to the horizon is 208.8 mi.

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Answer:

a = 7

Step-by-step explanation:

I think, what you need to do, is first understand how to find the mean of anything: It's quite simple, actually, just add up all the numbers, then divide that number by the number of numbers. So, let's put it in perspective:

10, 3, 4, a, 6, 9, 10

7 is the mean. 7 is the number of numbers.

If, to find the mean is: 10 + 3 + 4 + a + 6 + 9 + 10= 7a ÷ 7, then: 10 +3 + 4+ 6 + 9 +10= 42

42 plus what divided by 7 is the question now.

42 + a ÷  7= 7

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