Answer:
quadratic monomial, quadratic trinomial, constant monomial, linear monomial, quadratic binomial, linear binomial.
Step-by-step explanation:
two quadratic trinomials each have a degree-2, degree-1, and degree-0 term. It is possible that the coefficients of all or some of the terms cancel each other while adding or subtracting the polynomials.
The product would be -4984.
Answer:
(x+6)(x+2) is the factored equation
(-6, -2) is the coordinates
Step-by-step explanation:
find what multiplies to be 12 and adds to be 8
set each factor equal to 0 and solve for x, which is the coordinates
Answer for this question: X < -20
Answer:
![6x^{3}+16x^{2} +6x-12](https://tex.z-dn.net/?f=6x%5E%7B3%7D%2B16x%5E%7B2%7D%20%2B6x-12)
Step-by-step explanation:
To calculate the result of that mutiplication you have to firs evaluate the first term of the second function multipying the whole first function, woudl be like this:
![(3x)(2x^{2}+6x+6)= 6x^{3}+18x^{2} +18x](https://tex.z-dn.net/?f=%283x%29%282x%5E%7B2%7D%2B6x%2B6%29%3D%206x%5E%7B3%7D%2B18x%5E%7B2%7D%20%2B18x)
Now that you have this, you multiply the second term from the second function to obtain:
![(-2)(2x^{2}+6x+6)= -4x^{2}-12x-12](https://tex.z-dn.net/?f=%28-2%29%282x%5E%7B2%7D%2B6x%2B6%29%3D%20-4x%5E%7B2%7D-12x-12)
Now you just have to add both results:
![6x^{3}+18x^{2} +18x](https://tex.z-dn.net/?f=6x%5E%7B3%7D%2B18x%5E%7B2%7D%20%2B18x)
+ ![-4x^{2}-12x-12](https://tex.z-dn.net/?f=%20-4x%5E%7B2%7D-12x-12)
And the result of the sum would be:
![6x^{3}+16x^{2} +6x-12](https://tex.z-dn.net/?f=6x%5E%7B3%7D%2B16x%5E%7B2%7D%20%2B6x-12)