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nekit [7.7K]
3 years ago
6

Answers to the blank please

Mathematics
1 answer:
lara [203]3 years ago
5 0

Answer:

Step-by-step explanation:

MP=NQ

3x-2=2x+8

x=10

MP=3x-2=28

NQ=2x+8=28

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Find the size of angle YZX
Tasya [4]

Answer:

21.001 cm

Step-by-step explanation:

The diagram shows right triangle with

Hypotenuse ZY = 22.3 cm

Leg XY = 7.5 cm

By the Pythagorean theorem,

XY^2+XZ^2=ZY^2\\ \\7.5^2+XZ^2=22.3^2\\ \\XZ^2=22.3^2-7.5^2\\ \\XZ^2=(22.3-7.5)(22.3+7.5)\\ \\XZ^2=14.8\cdot 29.8\\ \\XZ^2=441.04\\ \\XZ=\sqrt{441.04}\approx 21.001\ cm

3 0
3 years ago
The radius of a sphere is measured to be 3.0 inches. If the measurement is correct within 0.01 inches, use differentials to esti
Zarrin [17]

Answer:

ΔV = 0.36π   in³

Step-by-step explanation:

Given that:

The radius of a sphere = 3.0

If the measurement is correct within 0.01 inches

i.e the change in the radius Δr = 0.01

The objective is to use differentials to estimate the error in the volume of sphere.

We all know that the volume of a sphere

V =  \dfrac{4}{3} \pi r^3

The differential of V with respect to r is:

\dfrac{dV}{dr }= 4 \pi r^2

dV = 4 πr² dr

which can be re-written as:

ΔV = 4 πr² Δr

ΔV = 4 × π × (3)² × 0.01

ΔV = 0.36π   in³

5 0
3 years ago
Please need help i need help i need help
xeze [42]

Set each expression from the parentheses equal to 0 separately like so:

Equation 1: x - 4 = 0

Equation 2: -5x + 1 = 0

Now for each equation solve for x!

Equation 1:

x +(- 4 + 4) = 0 + 4

x = 4

Equation 2:

-5x +( 1-1) = 0 - 1

-5x/ -5 = -1 / -5

x = 1/5

Check:

(4 - 4)(-5*4 + 1)

(0) (-20 + 1)

(0) (-19)

0 = 0 -------------------------> correct!

(1/5 - 4)(-5 * 1/5 + 1)

(-19/5)(-1 + 1)

(-19/5)(0)

0 = 0 -------------------------> correct!

smaller x = 1/5

larger x = 4

Hope this helped!

8 0
3 years ago
Read 2 more answers
-5⁄2 a + 5 = 25 find a
horsena [70]

Answer:

The answer is 8

Step-by-step explanation:

-5/2 x 8= 20 and if you add 5 it is 25.

8 0
3 years ago
Read 2 more answers
Solve x2 + 8x − 3 = 0 using the completing-the-square method.
lisabon 2012 [21]
(a+b)^2=a^2+2ab+b^2\\------------------\\\\x^2+8x-3=0\ \ \ |add\ 3\ to\ both\ sides\\\\x^2+2x\cdot4=3\ \ \ |add\ 4^2\ to\ both\ sides\\\\x^2+2x\cdot4+4^2=3+4^2\\\\(x+4)^2=3+16\\\\(x+4)^2=19\iff x+4=-\sqrt{19}\ or\ x+4=\sqrt{19}\\|subtract\ 4\ from\ both\ sides\\\\\boxed{x=-4-\sqrt{19}\ or\ x=-4+\sqrt{19}}
3 0
3 years ago
Read 2 more answers
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