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N76 [4]
3 years ago
15

in the year 2001, a person bought a new car for $22000. for each consecutive year after that, the value of the car depreciated b

y 5%. how much would the car be worth in the year 2005, to the nearest hundred dollars
Mathematics
1 answer:
igomit [66]3 years ago
7 0

Answer:

To the nearest hundred dollars, the car will be worth $17,900 by 2005

Step-by-step explanation:

Firstly, we need to write the depreciation equation

We have this as:

V = I(1 - r)^t

V is the present value which is what we want to calculate

I is the initial value, the amount the cad was bought which is $22,000

r is the rate of change which is 5% = 5/100 = 0.05

t is the time difference which is 2005-2001 = 4

Substituting all these into the depreciation equation, we have it that

V = 22,000(1 -0.05)^4

V = $17,919.1375

To the nearest hundred dollars, that would be;

$17,900

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First I would do it like this.

12.5

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—————-

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12.5

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