HELPP ASAP!!step by step anwserssw

A pair of shoes was discounted 20% after the discount, the cost of the shoes is $100 what was the initial price

Lerok [7]

It is $80 dollars I think

8 0

3 years ago

Find the absolute value of 2 and 2 3rd and negative 9 over 4

gayaneshka [121]

we are given

absolute value of 2 and 2 3rd and negative 9 over 4

Firstly , we need write it in terms of expression

2 and 2 3rd is

$2+\frac{2}{3}$

so, we get as

$|2+\frac{2}{3} -\frac{9}{4} |$

now, we can simplify it

Firstly , we will find common denominator

$|\frac{2*12}{1*12} +\frac{2*4}{3*4} -\frac{9*3}{4*3} |$

$|\frac{24}{12} +\frac{8}{12} -\frac{27}{12} |$

we can see that

all denominators are same

so, we can combine numerators

$=|\frac{24+8-27}{12} |$

$=|\frac{5}{12} |$

$=\frac{5}{12}$ ..............Answer

6 0

3 years ago

martin spent 6 hours on homework every day . what percentage of the day did martin spend doing homework ?

Ann [662]

1/4 or .25 because 6 * 4 = 24 so 6 would be a quarter of 24

6 0

3 years ago

(20 point question) Samantha wants to use her savings of $1,150 to buy shirts and watches for her family. The total price of the

erastova [34]

Answer:

C

Step-by-step explanation:

7 0

3 years ago

The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability

Whitepunk [10]

Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let Y = the time taken to deliver a pizza.

The random variable Y follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

$f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.$

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

$P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70$

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let X = results of a certain blood test.

It is provided that the random variable X follows a Normal distribution with parameters $\mu = 60$ and $s = 18$ .

The probabilities of a Normal distribution are computed by converting the raw scores to z-scores.

The z-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

$P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z$

The percentage of results more than 45 is: $0.7967\times100=79.67\%$

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

$P(X$

The percentage of results less than 85 is: $0.9177\times100=91.77\%$

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

$P(75$

The percentage of results are between 75 and 90 is: $0.1558\times100=15.58\%$

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

$P(20$

Then the probability that the results outside the range 20 to 100 is: $1-0.9736=0.0264$ .

The percentage of results outside the range 20 to 100 is: $0.0264\times100=2.64\%$

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

4 0

3 years ago