When meiotic cell division occurs, a diploid parent cell experiences cell division to produce four haploid cells. Thus, if three parent cells undertake meiosis, <u>twelve haploid cells</u> will be created.
It should be taken into consideration the presence of frameshift mutations. Frameshift mutation, due to addition or deletion of a base, results in the change of reading frame and consequently in changed protein. But it is known that 3 nucleotides on mRNA code for the specific amino acid. If the number of inserted or deleted nucleotides is 3, it will result in the absence<span> of only 1 amino acid which is not expected to drastically change protein sequence.
Knowing all this, it can be concluded the following:
</span>
<span>-/-/+/-/- <u>OK </u>- Due to 4 deletions and 1 insertion, effectively only 3 nucleotides are missing.
</span>+/-/+ <u>Not OK</u> - Due to 1 deletion and 2 insertions, effectively only 1 nucleotide is added leading to the frameshift mutation.
+/-/+/- <u>OK </u>- Due to 2 deletions and 2 insertions, a number of nucleotides remain the same.
+/+/-/+ <u>Not OK</u> - Due to 1 deletion and 3 insertions, effectively only 2 nucleotides are added and the frameshift mutation occurs.
-/+ <u>OK </u>- Due 1 deletion and 1 insertion, a number of nucleotides remain the same.
<span>- <u>Not OK</u> - Due to 1 deletion, the frameshift mutation occurs.
</span>-/-/-/-/-/- <u>OK </u>- <span>Due to 6 deletions, it will be deleted 2 amino acids and the protein will be nearly normal.</span>
<span>+/+/+ <u>OK </u>- Due to 3 insertions, 1 amino acid will be added in excess.
</span>-/- <u>Not OK</u> - Due to 2 deletions, the frameshift mutation occurs.
Density...
Fire bricks absorb many btu’s, so once heated up only a small flame is required to maintain that heat/temperature.
The fire brick composition is mostly materials like alumina silica sand, clay, not very porous.
The ability of a substance to burn is flammability.
Answer:
Concentration = 0.011 M
Explanation:
Molarity is given by dividing number of moles by volume in Liters
Molarity = moles/volume
But;
Number of moles = mass/molar mass
= 10 g/ 74.55 g/mole
= 0.134 moles
Therefore;
Molarity = 0.134 moles/12 L
= 0.011 M