Fragmentation is the breaking of the body into parts and then the organism develops all the parts of the body. The fragmentation is the type of reproduction in lower organisms. The fragments which are produced can develop into new organisms.
<span>The answer is Haploid spores germinate to give rise to protonema, which later develops into a sporophyte.</span>
A protonema (plural: protonemata) is a
thread-like chain of cells that forms the earliest stage (the haploid phase) of a bryophyte life
cycle..
<span>A haploid gametophyte ( each of whose cells contains a fixed number of
unpaired </span>chromosomes) gives rise to a <span>diploid sporophyte</span>,.
Gametophytes produce haploid sperm and eggs which fuse to form diploid zygotes
that grow into sporophytes.
A heart pound? I'm guessing lmaoooo
Your question was incomplete (please check below the full content). The evidence that supports the prokaryotic origins of mitochondria and chloroplasts do not include multiple DNA copies associated with inner membranes.
<h3>What is organellar DNA?</h3>
The organellar DNA is the genome contained within mitochondria and chloroplasts, which is independent of nuclear eukaryotic DNA.
The organellar DNA contains multiple DNA molecules, which are found in association with the inner membrane, ant is not found in prokaryotic life forms.
The complete question in this case is: "Evidence that supports the prokaryotic origins of mitochondria and chloroplasts are the presence of mitochondria, a eukaryote engulfing prokaryotic photosynthetic cells, and non-photosynthetic eukaryotes, EXCEPT."
The endosymbiotic theory states that mitochondria and chloroplasts evolved from prokaryotic microorganisms that entered into a primitive eukaryotic cell.
This theory is supported by certain features of mitochondria and chloroplasts such as a similar size to prokaryotes.
In conclusion, evidence do not include the arrangement of the organellar DNA.
Learn more about mitochondrial DNA here:
brainly.com/question/1563697
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Answer:
a) the selection intensity is 21bushels/acre
b) the response to selection is 12bushels/acre
c) The heritability is 0.57 (two decimal places)
Explanation:
Given:
mean grain yield population=72bushels/acre
mean grain yield selected individuals=93bushels/acre
mean grain yield new population=84busgels/acre
a) The selection intensity is given by:
SI=mean grain yield selected individuals-mean grain yield population=93-72=21bushels/acre
b) The response to selection is:
RS=mean grain yield new population-mean grain yield population=84-72=12bushles/acre
c) The heritability of grain yield is:
H=RS/SI=12/21=0.57
