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2 years ago

Vincente slept 5 more hours this past weekend than Dorinda. Dorinda only slept half as many hours this weekend as Sade.

Mathematics

1 answer:

Ahat [919]2 years ago

4 0

Answer/Step-by-step explanation:

*An average person on Earth needs 8.5 hours of sleep each night*

1. V - 5 = D

2. D ÷ 2 = S

3. S + 5 = V

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An artist wants to make alabaster pyramids using a block of alabaster with a volume of 576 cubic inches. She plans to make each

8_murik_8 [283]

Volume of pyramid:

$V= \dfrac{1}{3} \cdot A \cdot H$

A - base area
H - height

First count volume of one pyramid:

$V=\dfrac{1}{3} \cdot 3 \cdot 4=4 [\hbox{inch}^3]$

So by using 576 inch^3 you can make 576 : 4 = 144 pyramids

3 0

3 years ago

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Rachel made 28 hats. Rachel made 7 times as many hats as Greg. Let n be the number of hats that Greg made.

il63 [147K]

Answer:

28/7=n is what I believe would be the answer

5 0

3 years ago

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The coordinate of centroid of a triangle whose vertices are (1,3,-2), (4,5,0), (6,3,9) is = ……………….

Dominik [7]

Answer:

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

Step-by-step explanation:

Given

$(x_1,y_1,z_1) = (1,3,-2)$

$(x_2,y_2,z_2) = (4,5,0)$

$(x_3,y_3,z_3) = (6,3,9)$

Required

Determine the coordinates of the centroid

Represent the coordinates with C.

C is calculated as follows:

$C = (\frac{1}{3}(x_1+x_2+x_3),\frac{1}{3}(y_1+y_2+y_3),\frac{1}{3}(z_1+z_2+z_3}))$

Substitute values of x and y in the given equation

$C = (\frac{1}{3}(1+4+6),\frac{1}{3}(3+5+3),\frac{1}{3}(-2+0+9}))$

$C = (\frac{1}{3}(11),\frac{1}{3}(11),\frac{1}{3}(7}))$

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

The above is the coordinate of the centroid

8 0

2 years ago

Find the value of 1 and 1/10-1/5

Andreyy89

9514 1404 393

Answer:

9/10

Step-by-step explanation:

(1 1/10) - 1/5 = (1 1/10) -2/10 = 1 + (1/10 -2/10) = 1 -1/10 = 9/10

1.1 -0.2 = 0.9 = 9/10

5 0

3 years ago

The total current of a parallel circuit is 9+j2 amps and the current of one component of the circuit is 3−j5 amps. What is the c

stealth61 [152]

Apply law of total resistance in parallel circuit

$\\ \tt\hookrightarrow \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

$\\ \tt\hookrightarrow \dfrac{1}{9+2J}=\dfrac{1}{3-5j}+\dfrac{1}{R_2}$

$\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{1}{9+2J}-\dfrac{1}{3-5J}$

$\\ \tt\hookrightarrow \dfrac{1}{R_2}=\dfrac{3-5J-9-2J}{(9+2J)(3-5J)}$

$\\ \tt\hookrightarrow R_2=\dfrac{(9+2J)(3-5J)}{-6-7J}$

4 0

2 years ago