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3 years ago

13

What is the answer on this 3abc + bc - a

1 answer:

Alex17521 [72]3 years ago

8 0

3b^2c^2 is the answer i’m pretty sure

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Simplify the following expression and write in standard form: 3 x (6y - 4y + 5x) PLEASE HELP

mylen [45]

Answer: 15x^2+6xy

Step-by-step explanation: 3x(6y−4y+5x)

(3x)(6y+−4y+5x)

(3x)(6y)+(3x)(−4y)+(3x)(5x)

18xy−12xy+15x^2

15x^2+6xy

8 0

3 years ago

Can someone help me please? Am I right or no?

Juliette [100K]

The figure consists of three objects, a rectangle, a trapezoid, a triangle

Find the area of the rectangle
The rectangle is 16 in long and 9 in wide
a₁ = l × w
a₁ = 16 × 9
a₁ = 144 in²

Find the area of the trapezoid
The base of trapezoid is 31 in and 16 in, and the height is 35 - 20 = 15 in.
a₂ = 1/2 × (a + b) × h
a₂ = 1/2 × (31 + 16) × 15
a₂ = 1/2 × 47 × 15
a₂ = 352.5 in²

Find the area of the triangle
The base of the triangle is 31 in, the height is 20 in
a₃ = 1/2 × b × h
a₃ = 1/2 × 31 × 20
a₃ = 310 in²

Add the area together
a = a₁ + a₂ + a₃
a = 144 + 352.5 + 310
a = 806.5

The answer is 806.5 in²

4 0

2 years ago

In a scale drawing of a garden, a distance of 35 feet is represented by a line segment 4 inches long. on the same drawing, what

nalin [4]

Answer:

$122.5\ ft$

Step-by-step explanation:

we know that

Using proportion

$\frac{35}{4}\frac{ft}{in}=\frac{x}{14}\frac{ft}{in}\\ \\x=35*14/4\\ \\x=122.5\ ft$

7 0

2 years ago

Nonlinear Systems of Equations

zheka24 [161]

The square root and cube root identities are proved.

According to the statement

we have to find that the use of the square root identity (x − y)2 = x2 − 2xy + y2

And use of cube root identity a3 + b3 = (a + b)(a2 − ab + b2).

So, For this purpose, we know that the

A. Let us assume the two conditions.

So,

2x + 3y = 6 -(1)

4x + 7y = 8 -(2)

Here we use elimination method

So, Multiply 4 with (1) and 2 with (2)

8x + 12y = 24

8x + 14y = 16

Now eliminate x from these equations

-2y = 8

here y is -4.

and the x become

2x + 3y = 6

2x -12 = 6

2x = 18

x = 9.

B. For the use of identity $(x- y)^{2} = x^{2} - 2xy + y^{2}$

Let us assume a number 26 and 28 then fill it in the condition then

$(28- 26)^{2} = 28^{2} - 2(28)(26) + 26^{2}$

Then

$(28- 26)^{2} = 784 - 1456 + 676$

$(28- 26)^{2} = 4$

And we have to prove the cube root identity then

The identity is

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

Then let us assume the number 8 and 9 then

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

$8^{3} + 9^{3} = (8 + 9)(8^{2} - 8*9 + 9^{2})$

$8^{3} + 9^{3} = (17)(64 - 72 + 81)$

$8^{3} + 9^{3} = (17)(73)$

$8^{3} + 9^{3} = (1241)$

Hence by this way we prove the square and cube root identities.

So, The square root and cube root identities are proved.

Learn more about square root and cube root here

brainly.com/question/661780

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3 0

1 year ago

Please help i will mark Brainly

Anit [1.1K]

Answer:

1.2

Step-by-step explanation:

Did the Math, hope I helped.

6 0

3 years ago