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Strike441 [17]
3 years ago
9

Un groupe d'amis décide d'organiser une sortie au restaurant. Ils prennent contact avec un restaurateur qui leur propose une for

mule à 20 € par convive. Le jour de la sortie, cinq personnes ne peuvent venir. Les participants doivent alors payer 22 € par personne. Combien de personnes étaient initialement prévues ?
Mathematics
1 answer:
Rainbow [258]3 years ago
6 0

Answer:

55

Step-by-step explanation:

Assuming that, initially, there were x people at the time of planning.

As given that, initially, the cost for 1 person = € 20

So, Total cost = € 20x ...(i)

As on the day of the outing, five people cannot come, so the number of people on the outing = x-5.

Now, due to the lesser number of people, i.e (x-5), the cost for 1 person = € 22.

Total cost = € 22(x-5) ...(ii)

As total cost remains the same, so equation the total cost from equations (i) and (ii), we have

20x= 22(x-5) \\\\\Rightarrow 20x=22x-22\times 5 \\\\\Rightarrow 22x-20x= 110 \\\\\Rightarrow 2x=110 \\\\\Rightarrow x=110/2=55.

Hence, at the time of planning, there were 55 people.

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Answer:

h0 : u = 15 amps

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Note: h0 is the null hypothesis

h1 is the alternative hypothesis

u is the mean

¥ is used to represent 'not equal to'

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If Amanda ran 3/8 of a mile on Wednesday, how much more did she run on Monday and Tuesday than on Wednesday
dimulka [17.4K]
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3 years ago
Find all values of k for which the function y=sin(kt) satisfies the differential equation y′′+16y=0. Separate your answers by co
VashaNatasha [74]

Answer: k = 4, k = -4 and k = 0.

Step-by-step explanation:

If we have y = sin(kt)

then:

y' = k*cos(kt)

y'' = -k^2*son(x).

then, if we have the relation:

y'' - y = 0

we can replace it by the things we derivated previously and get:

-k^2*sin(kt) + 16*sin(kt) = 0

we can divide by sin in both sides (for t ≠0 and k ≠0 because we can not divide by zero)

-k^2 + 16 = 0

the solutions are k = 4 and k = -4.

Now, we have another solution, but it is a trivial one that actually does not give any information, but for the diff equation:

-k^2*sin(kt) + 16*sin(kt) = 0

if we take k = 0, we have:

-0 + 0 = 0.

So the solutions are k = 4, k = -4 and k = 0.

4 0
3 years ago
Please help i have an exam next week and im really stuck on this
ruslelena [56]

Answer:

Area = 96 square cm

Step-by-step explanation:

Area of the figure = (2 x Area of triangles) + Area of square

Area \ of \ triangle = \frac{1}{2} \times base \ height = \frac{1}{2} \times 8\times 4 = 16cm^2\\\\Area \ of \ square = side \times side = 8 \times 8 = 64cm^2

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6 0
3 years ago
Read 2 more answers
Which expression would be equivalent to: Which expression would be equivalent to: \frac{1+b}{2} - 3(a-1)
IrinaVladis [17]

Answer:

\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}

Step-by-step explanation:

Given

\frac{1+b}{2} - 3(a-1)

Required

An equivalent expression

\frac{1+b}{2} - 3(a-1)

Take LCM

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 2*3(a-1)}{2}

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6(a-1)}{2}

Open bracket

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6a+6}{2}

Collect like terms

\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+6+1}{2}

\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}

Hence, an equivalent expression is:

\frac{b- 6a+7}{2}

8 0
3 years ago
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