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kondaur [170]
2 years ago
6

For these two rules, the second number in the ordered pair is always three times greater than the first number. If the relations

hip between the two numbers in each ordered pair is the same, the graph will be: Not graph-able A straight line A circle An exponential curve A parabolic curve
Mathematics
1 answer:
spayn [35]2 years ago
3 0
Well this factor has to the answer b.) hope I helped.
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What is the circumference of a circle whose radius is 20 feet? Leave answer in terms of π.
lesantik [10]

Answer:

What is the circumference of a circle whose radius is 20 feet? Leave answer in terms of π.  

A)  10π feet  

B)  20π feet  

<u> C)  40π feet  </u>

 D)  100π feet

Step-by-step explanation:

circumference = 2πr

circumference=2×π×20

circumference=40π

5 0
3 years ago
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Select the correct answer.
Ratling [72]
I think it’s D but not completely sure!
5 0
2 years ago
Please answer this and I’ll make you Brainly
murzikaleks [220]

Answer:

-4 = ?

Step-by-step explanation:

<u>Step 1:  Substitute -1 for x</u>

7x^3 + 5x^2 - 2 = ?

7(-1)^3 + 5(-1)^2 - 2 = ?

7(-1) + 5(1) - 2 = ?

-7 + 5 - 2 = ?

-4 = ?

Answer: -4 = ?

3 0
2 years ago
What is the circumference of the circle with radius 8cm in terms of ?
Verizon [17]

Answer:

Step-by-step explanation:

C = 2\pi *r\\r = 8cm\\C = 2*\pi*8\\C = 16 \pi cm

6 0
3 years ago
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Tan39= x/68<br> Plz help. Will give brainliet
lesya [120]

Answer:

\huge\boxed{x \approx 55}

Step-by-step explanation:

We need to note that this is an equation, in which we can solve for x.

tan(39) = \frac{x}{68}

We can use a calculator to find the tangent of 39 - we type 39 into the calculator then press the "TAN" button to find it's tangent. We find that to be around 0.81.

We now have the formula simplified down to 0.81 = \frac{x}{68}. To solve for x, we want to isolate it on one side, so we can multiply both sides by 68 to get rid of the fraction.

We know have 0.81 \cdot 68 = x

0.81 \cdot 68 = 55.08 \approx 55, so x is approximately 55.

Hope this helped!

6 0
2 years ago
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