1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatyana61 [14]
3 years ago
14

For brainlest pls ..

Mathematics
2 answers:
Irina-Kira [14]3 years ago
5 0

Answer:

A = 39 ft²

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = \frac{1}{2} h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 6, b₁ = 9, b₂ = 4 , then

A = \frac{1}{2} × 6 × (9 + 4) = 3 × 13 = 39 ft²

mixer [17]3 years ago
4 0
39 (Hope you understand )

You might be interested in
The sum of two numbers is equal to 63 and their differences are 12. Find the numbers.
icang [17]

Answer:

13.5

Step-by-step explanation:

5 0
3 years ago
Can someone help me?
mestny [16]

Answer:

Step-by-step explanation:

To do this, we must use the unit circle. At the angle \frac{\pi }{6} the coordinate pair is (\frac{\sqrt{3} }{2}, \frac{1}{2}) and the hypotenuse is 1

Now that we know these we can start using the trig functions

sin = y

cos = x

tan = \frac{y}{x}

And the other functions would be the reciprocal of these

csc = \frac{1}{y}

sec = \frac{1}{x}

cot = \frac{x}{y}

This would mean that

sinx = \frac{1}{2}

cosx =\frac{\sqrt{3} }{2}

tanx =\frac{1}{\sqrt{3} } or \frac{\sqrt{3} }{3} if you're supposed to rationalize your denominators

cscx = 2

secx = \frac{2}{\sqrt{3} } or \frac{2\sqrt{3} }{3}

cot = \sqrt{3}

6 0
3 years ago
What factors multiply to -80 and add to 6
forsale [732]

80 = -1(80), -2(40), -4(20), -5(4),

Total answers include: -81, 79, -42, 16, -9, and 1.

None of them add up to 6!

Are you doing polynomial equations?

If so, you can solve it the hard way.

x^2 + 6x -80 = 0

(x^2 + 6x + 9) - 80 = 9

(x+3)^2 = 89

(x+3) = 9.43

x = 6.43

If you're not doing those then I'm afraid your question has no answer.

Hope that helps!



7 0
3 years ago
Pls help me and thank ya!!
algol13

Answer:

Option 1

Step-by-step explanation:

Rational numbers do not have infinite decimals.

Option 1:

-5, 3/4 and √49 are all rational. Correct

√49 = 7

3/4 = 0.75

-5 = -5

Option 2:

1/4 = 0.25

5 = 5

√12 = 3.4641...

Incorrect

Option 3:

-1/2 = -0.5

-3 = -3

√8 = 2.82841...

Incorrect

Option 4:

1/7 = 0.142857...

9 = 9

√11  = 3.31662...

Incorrect

5 0
3 years ago
How do I do this?<br>*Look at the directions in the photo*​
lora16 [44]

Answer:

Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2

Step-by-step explanation:

We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\

As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2

For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2

For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2

Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2

7 0
3 years ago
Other questions:
  • (5•2+20/2)+(10•2/2+5)
    9·1 answer
  • The number of years a truck is owned, x, and the cost of annual repairs in dollars, f(x) , can be modeled by a linear function.
    9·2 answers
  • Bernard is helping his mother measuring fabric for outfit that she is making. She needs 11.5 yards of fabric. How many more feet
    14·2 answers
  • A cafeteria worker is wondering how student lunch prices at a high school have changed over time. She researches lunch prices fo
    6·2 answers
  • What are the steps for this {3x\ -5}{3}=11x\ -5?
    15·2 answers
  • WHAT VARIES MORE 6.6 OR 4.3: NO LINKS
    15·2 answers
  • What is the solution to this system of equations? ​
    13·1 answer
  • How do you find the f(6)​
    8·1 answer
  • Please help me! I need help with this question.
    5·2 answers
  • Which TWO situations illustrate that the sum of opposite numbers is zero?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!