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Arlecino [84]
3 years ago
14

Will give brainliest

Mathematics
1 answer:
Phoenix [80]3 years ago
3 0

Answer: The equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10 is y = (-2/5)x - 2

Step-by-step explanation: The equation of a straight line is given by:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

The slope of the line 2x + 5y = 10 is:

2x + 5y = 10

5y = -2x + 10

y = -2/5x + 10

Hence the slope of the line 2x + 5y = 10 is -2/5

Since both lines are parallel, hence the slope of the other line is the same (-2/5). Hence the equation of the line is:

The equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10 is y = (-2/5)x - 2

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Reil [10]
2x2x5x5 or 2^2*5^5 hope this helps!
6 0
3 years ago
Point F(-17,8) is rotated 180° about the origin what are the coordinates of image f?
dlinn [17]

Answer:

F'(17, - 8 )

Step-by-step explanation:

Under a rotation about the origin of 180°

a point (x, y ) → (- x, - y ), thus

F(- 17, 8 ) → F'(17, - 8 )

5 0
3 years ago
How can you use x- and y- intercepts to graph an equation
sasho [114]

Answer:

Since two points determine any line, we can graph lines using the x- and y-intercepts. To find the x-intercept, set y = 0 and solve for x. To find the y-intercept, set x = 0 and solve for y. This method of finding x- and y-intercepts will be used throughout our study of algebra because it works for any equation.

Please mark brainliest :)

4 0
3 years ago
type the slope intercept equation of the line that passes through the point (1,1)&(7,4) enter fraction in simplest form
9966 [12]
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 1}}\quad ,&{{ 1}})\quad 
%   (c,d)
&({{ 7}}\quad ,&{{ 4}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{4-1}{7-1}\implies \cfrac{3}{6}\implies \cfrac{1}{2}

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=\cfrac{1}{2}(x-1)\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-1=\cfrac{1}{2}x-\cfrac{1}{2}\implies y=\cfrac{1}{2}x-\cfrac{1}{2}+1\implies y=\cfrac{1}{2}x+\cfrac{1}{2}
5 0
3 years ago
The sum of the squares of 2 consecutive negative integers is 41. What are the numbers? Which of the following equations is the r
VARVARA [1.3K]
Answer:
The two numbers are -5 and -4

Explanation:
Assume that the first number is x and that the second number is x+1.
We know that the sum of their squares is 41. This means that:
x² + (x+1)² = 41

We will expand the brackets and factorize to get the value of x as follows:
x² + (x+1)² = 41
x² + x² + 2x + 1 = 41
2x² + 2x + 1 - 41 = 0
2x² + 2x - 40 = 0
We can divide all terms by 2 to simplify the equation:
x² + x - 20 = 0 ..........> equation required in part II

Now, we can factorize this equation to get the values of x:
x² + x - 20 = 0
(x-4)(x+5) = 0
either x = 4 .........> rejected because we know that x should be negative
or x = -5 ...........> accepted

Based on the above calculations, the two numbers are -5 and -4

Hope this helps :)

8 0
4 years ago
Read 2 more answers
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