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Elden [556K]
3 years ago
5

The box plot below represents some data set. What percentage of the data values are greater than 48?

Mathematics
1 answer:
Fed [463]3 years ago
4 0

Answer:

25%

Step-by-step explanation:

Each part is 25%, so if we are looking at greater than 48 it would be 25

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10ac-x/11=-3 solve for a
Masja [62]
1) You'll have to get raid of the fraction by multiplying 10ac by 11, x/11 by 11 which the 11's cancels out and -3 multiplied by 11 .
2)Now you have 10ac -x = -33. Add x on both sides of the equal sign you get 10ac = -33 + x
3) Divide both sides by 10c to get "a" by itself, so "a" = -33+x divided by 10c
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3 years ago
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7. Solve the equation.<br> 6(x - 2) = 36<br> 0-8<br> 04<br> 04<br> 08<br> What one
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Answer:

8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

6(x - 2) = 36

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Divide 6 on both sides:                     x - 2 = 6
  2. Add 2 on both sides:                         x = 8
6 0
3 years ago
How do you simplify that question? For algebra 1.
motikmotik
\left( \sqrt{x^{-3}} \right)^5 =  \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }


<span>Explanation for the last step:</span>
\sqrt{x^{15}}= \sqrt{x^{14}*x}= \sqrt{x^{14}}* \sqrt{x} =x^{ \frac{14}{2} }* \sqrt{x} =x^7 \sqrt{x}

7 0
3 years ago
A poster is to have a total area of
Neko [114]

Answer:

Dimensions of printed area

w = 8.95 cm

h = 13.44 cm

A(max) = 120.28 cm²

Step-by-step explanation:

Lets call  " x "  and  "y" dimensions of the poster area  ( wide and height respectively) . Then

A(t)  =  180 cm²  = x*y      y  =  180/ x

And the dimensions of printed area is

A(p) = ( x - 2 ) * ( y - 3 ) then  as y  = 180/x we make A function of x only so

A(x)  =  ( x - 2 ) * ( 180/x  - 3 )     ⇒  A(x)  = 180 - 3x - 360/x +6

A(x)  = - 3x  - 360 /x + 186

Taking derivatives on both sides of the equation we get:

A´(x)  = -3  + 360/ x²  

A´(x)  = 0    -3  + 360/ x²  = 0     -3x²  +  360  = 0

x²  = 120       ⇒   x = √120       x  =  10.95 cm

And  y  =  180 / 10.95 ⇒         y  =  16.44 cm

Then x and y are the dimensions of the poster then according to problem statement

w of printed area is    x - 2  =  10.95 - 2   =  8.95 cm

and  h  of printed area is  y - 3  = 16.44 - 3  = 13.44 cm

And the largest printed area is  w * h  = ( 8.95)*(13.44)

A(max) = 120.28 cm²

   

 

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Your answer should be <span>x>2</span>
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