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madam [21]
3 years ago
13

10 gallons drank 5 cups how many left

Mathematics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:

155

Step-by-step explanation:

16 cups in a gallon

16 x 10 = 160

160 - 5 = 155

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Ahh help plss!! thank u
AnnZ [28]
Basically you’re multiplying them both
(x^3 + 2x - 1)(x^4 - x^3 + 3)

so you need to make sure you multiply each one, if you do it right, you should end up with
x^7 - x^6 + 3x^3 + 2x^5 - 2x^4 + 6x -x^4 +x^3 -3

simplify by adding like terms
x^7 - x^6 + 2x^5 - 3x^4 + 4x^3 + 6x - 3

your answer would be the third option
4 0
3 years ago
Lou has a solid clay brick in the shape of a rectangular prism with a length of 8 inches, a width of 3.5 inches, and a height of
Marta_Voda [28]

Answer:

The weight of the brick is 60 ounce to the nearest ounce

Step-by-step explanation:

In this question, we are asked to calculate the weigh of Lou’s brick given the dimensions of the shape of the brick and the weight of the clay.

To answer this question quite aptly, we need to know exactly the volume of the rectangular prism given the dimensions we have in the question.

To calculate this volume , we simply use the measurements we have to get it.

mathematically the volume of a rectangular prism is simply V = w * h * l

where w , h and l are width, height and length respectively.

now let’s calculate!

V = 3.5 * 2.25 * 8 = 63 inches^3

Now we need to know what the brick weigh in ounce. We already have the weight of the clay. now this is equal to the volume of the brick divided by the weight of the clay.

Mathematically this is = 63/1.055 = 59.72 ounce which is 60 ounce to the nearest ounce

7 0
3 years ago
Read 2 more answers
If x° – 7x2 + kx + 15 is exactly divisible by (x – 3), then find the value of k.​
faltersainse [42]

Answer:

k=4

Step-by-step explanation:

3 0
3 years ago
Paper rectangle ABCD is folded in such a way that the fold passes through point B, and so A coincides with point H where H ∈ CD.
aivan3 [116]

The answer is BC = 38.22 cm.

<u>Step-by-step explanation</u>:

We have, ∠BKD = 120° ,BK = 28 cm, Draw a perpendicular from point K on BC let it intersect at point M.  In right angled ΔBMK, ∠BKM=30° and BK = 28 cm

sin30° = perpendicular/hypotenuse

1/2 = BM/BK

1/2 = BM/28

BM= 14 cm

Now , In right angled ΔBMK ,

cos30° = base/hypotenuse

√3/2 = MK/28

MK = 14√3 = 24.22 cm

KMCD is a square  MK = MC = 24.22 cm

also, BC = BM + MC , putting values of BM & MC we get :

BC = 14 cm + 24.22 cm

BC = 38.22 cm.

5 0
3 years ago
What is the perimeter of the trapezoid graphed below?
Zanzabum
To get the perimeter of the trapezoid, we will add the lengths of the 4 sides together.
So, first we will need to get the length of each side.

Base of trapezoid = 8 - 2 = 4 units
The upper edge of the trapezoid = 6 - 4 = 2 units

Now, for the two side edges, we can note that they are both equal. So, we need to get only one length (as the other would be the same). I will get the length of the left side.
Coordinates of the start point are (2,4) which represent (x1,y1)
Coordinates of the end point are (4,9) which represent (x2,y2)
To get the distance between the two points, we will use the rule attached in the image below as follows:
distance = sqrt ((4-2)^2+(9-4)^2)
distance = √29
Therefore, each of the side edges equal √29 units

From the above, we can now easily get the perimeter as follows:
perimeter = 6 + 2 + √29 + √29
perimeter = 8 + 2√29 units

Based on the above calculations, the best choice would be:
D. 8 + 2√29 units

3 0
4 years ago
Read 2 more answers
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