Consider the cross-sectional right triangle shown in the figure.
One of its sides is the height of the pyramid, with length H. The other side is half of the square base, so its length is 81 m. The hypotenuse of this triangle is the height of one of the faces.
By right triangle trigonometry,

,
thus,

.
Answer: C) 52 m
Answer:
483 1/3%
Step-by-step explanation:
58/12
29/6
*100
2900/6
483 1/3
Answer:
Tom hit 13 red targets!
Step-by-step explanation:
Answer:
Step-by-step explanation:
From the table attached we find,
Number of shaded triangles = 1
Area of each shaded triangle = 256 square inches
Now we can complete the table following the same pattern,
Step number Number of shaded triangles Area of the shaded triangles
0 1 256
1 3 256 × 3 = 768
2 5 256 × 5 = 1280
3 7 256 × 7 = 1792
Answer:
Step-by-step explanation:
(a).
= x ( 2x + 1 ) = <em>2x² + x</em>
(b).
= 2( 2x + 1 )( 5x + 3 ) = <em>20x² + 22x + 6</em>
(c).
= 20x² + 22x + 6 - ( 2x² + x ) =
( 20x² - 2x² ) + ( 22x - x ) + 6 =
<em>18x² + 21x + 6</em>