Answer:
(2x100,000) 200,000,00
Step-by-step explanation:
200,000
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
Answer:
<em>i: </em>x=-2, x=1
<em>ii: </em>x=-1/2
Step-by-step explanation:
Quadratic form:
You solve <em>i </em>by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.
<em>"first"</em> would be 
, which would equal 
<em>"outside"</em> would be 
, which would equal 
<em>"inside"</em> would be 
, which would equal 
<em>"last" </em>would be 
, which would equal 
Now you need to combine the terms so that they are one after the other
Combine like terms, and you should get:
i Solution
<em>You need to get the variable by itself.</em>
<em>Subtract two from both sides</em>
<em>Add one to both sides.</em>
ii Solution
<em>Add all the terms.</em>
