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Ann [662]
3 years ago
11

Can you tell me the answer please?​

Mathematics
2 answers:
8090 [49]3 years ago
6 0

Answer:

Not a function

Step-by-step explanation:

It fails the vertical line test. 2 points can not cross on this test

kolezko [41]3 years ago
4 0

Answer:

This graph is not a function.

Step-by-step explanation:

For every x value, it has more than one y value. The graph also doesn't pass the vertical line test.

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Find all solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically. (Enter your answer
Anuta_ua [19.1K]

Answer:

The solutions of the equation are 0 and 0.75.

Step-by-step explanation:

Given : Equation 16x^4 - 24x^3 +9x^2 =0

To find : All solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically ?

Solution :

Equation 16x^4 - 24x^3 +9x^2 =0

x^2(16x^2-24x+9)=0

Either x^2=0 or 16x^2-24x+9=0

When x^2=0

x=0

When 16x^2-24x+9=0

Solve by quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-24)\pm\sqrt{(-24)^2-4(16)(9)}}{2(16)}

x=\frac{24\pm\sqrt{0}}{32}

x=\frac{24}{32}

x=\frac{3}{4}

x=0.75

The solutions of the equation are 0 and 0.75.

For verification,

In the graph where the curve cut x-axis is the solution of the equation.

Refer the attached figure below.

7 0
3 years ago
What is the slope of the line that passes through the points (3, -2) and (9, -2)?
ICE Princess25 [194]

m=(-2+2)/(9-6)=0/3=0

m=0

7 0
3 years ago
At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more
I am Lyosha [343]

Answer:

The probability is  P( X \le 4 ) = 0.0054

Step-by-step explanation:

From the question we are told that

   The percentage that are on time is  p =  0.76

   The  sample size is n =  11

   

Generally the percentage that are not on time is

     q =  1- p

     q =  1-  0.76

     q = 0.24

The  probability that no more than 4 of them were on time is mathematically represented as

        P( X \le 4 ) =  P(1 ) +  P(2) + P(3) +  P(4)

=>     P( X \le 4 ) =  \left n } \atop {}} \right.C_1 p^{1}  q^{n- 1} +   \left n } \atop {}} \right.C_2p^{2}  q^{n- 2} +  \left n } \atop {}} \right.C_3 p^{3}  q^{n- 3}  +  \left n } \atop {}} \right.C_4 p^{4}  q^{n- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{11- 1} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{11- 2} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{11- 3}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{11- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{10} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{9} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{8}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{7}

= \frac{11! }{ 10! 1!}  (0.76)^{1}  (0.24)^{10} +   \frac{11!}{9! 2!}  (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!}  (0.76)^{3}  (0.24)^{8}  + \frac{11!}{7!4!}  (0.76)^{4}  (0.24)^{7}

P( X \le 4 ) = 0.0054

4 0
3 years ago
Can someone please help?
garri49 [273]

Answer:

this doesnt make sense

Step-by-step explanation:

5 0
3 years ago
F(x)=-x^2+6x+4<br><br>f(x)=−x <br><br>2<br><br> +6x+4
snow_lady [41]

Answer:

x = 3 - 2 (3)

Step-by-step explanation:

.

8 0
2 years ago
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