Graph and show work. Please. Helping a grandchild and I need to explain.
1 answer:
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<u>Answer-</u>
<em>The least squares regression equation using the school year (in number of years after 2000) for the input variable and the average cost (in thousands of dollars) for the output variable is "y=0.937x+12.765" .</em>
<u>Solution-</u>
The independent variable / input variable= x = Number of years after 2000 ( = year-2000)
The dependent variable / output variable = y = Average cost in thousands of dollars
(The table has been attached herewith.)
To find the regression equation for a group of (x,y) points,
We have to calculate the slope and y-intercept, then we can put those values in the equation y = mx + c ( Slope - Intercept formula)
We know that,
Putting the values from the table,
( ∵ Instead of 150,894 we have to put 150.894 as we have find the line for year and thousands of dollars )
Now, for the y-intercept,
Putting the values,
Now, putting the values of c and m, in the Slope-Intercept formula,
Answer:
Step-by-step explanation:
We are given;
- The equation of a line 6x-2y=4+6y
- A point (8, -16)
We are required to determine the equation of a line parallel to the given line and passing through the given point.
- One way we can determine the equation of a line is when we are given its slope and a point where it is passing through,
First we get the slope of the line from the equation given;
- We write the equation in the form y = mx + c, where m is the slope
That is;
6x-2y=4+6y
6y + 2y = 6x-4
8y = 6x -4
We get, y = 3/4 x - 4
Therefore, the slope, m₁ = 3/4
But; for parallel lines m₁=m₂
Therefore, the slope of the line in question, m₂ = 3/4
To get the equation of the line;
We take a point (x, y) and the point (8, -16) together with the slope;
That is;
Thus, the equation required is