About 38 cars. 300/8= 37.5 cars. There is no such thing as 0.5 of a car so round up to the nearest whole number.
A because if you use T3 it wouldn’t have make sense so only reasonable and solution that works is A
The answer is B. Yes; 4
Arithmetic sequence is the type of sequence of numbers which difference between each number will always remain constant
in the sequence above we could see the difference between one number with another is exactly 4:
15 + 4 = 19
19 + 4 = 23
23 + 4 = 27
F(x) = 3x + 7.....g(x) = 4x - 2
A. (f + g)(x)
3x + 7 + 4x - 2
7x + 5 <====
B. (f * g)(x)
(3x + 7)(4x - 2) =
3x(4x - 2) + 7(4x - 2) =
12x^2 - 6x + 28x - 14
12x^2 + 22x - 14 <===
C. f[g(x)]
3(4x - 2) + 7 =
12x - 6 + 7 =
12x + 1 <===
Answer:
0 < x < 12
Step-by-step explanation:
Since it's given that side a and side b both have a length of 6, side c has to be 0 < x < 12.
