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Tom [10]
3 years ago
8

Carl has 200 songs on his MP3 player of these songs 24 are country songs what is the percent of country songs he has

Mathematics
2 answers:
PolarNik [594]3 years ago
4 0
200 \ songs, 24 \ country \ songs
\\\ \frac {24}{200} = Percent \ Of \ Country \ Songs
\\\ \frac{24}{200} --\ \textgreater \  \frac{12}{100}
\\\ 12 \%
vlabodo [156]3 years ago
3 0
It would be 12 songs.

Divide 24 by 200.

24÷200=0.12

Multiply by 100 because percentages are out of 100.

0.12×100= 12

12%
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Galina-37 [17]

The percentage of the radioactive isotope left is 25.0000%.

<h3>What is the half life?</h3>

The half life of a radioactive isotope is the time that will elapse before only half of the number of original isotopes will remain.

Now;

We are told that;

Half life (t1/2) = 55 days

Time taken (t) =  115 days

Ratio of isotope remaining = N/No

Thus;

N/No = (1/2)^t/t1/2

N/No = (1/2)^115/55

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7 0
2 years ago
Write the equation of the line in slope-intercept form that has: slope: 3<br> point: (0,2)
goldenfox [79]

Answer:

y=3x+2

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7 0
3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
3 years ago
There are 12 students who wish to enroll in a particular course. there are only five seats left in the classroom. how many diffe
siniylev [52]
792 is the answer

(12*11*10*9*8)/5!=792
5 0
3 years ago
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