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Fittoniya [83]
3 years ago
9

In ΔLMN, l = 6.9 cm, m = 8.1 cm and n=8.8 cm. Find the measure of ∠N to the nearest 10th of a degree.

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

71.3

Step-by-step explanation:

trust me.. delta 2021

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What is the sum of the terms of the series (−1) + (−2) + (−3) + . . . + (−10)?
Murrr4er [49]
You can solve this problem by using the Gauss method. The Gauss method is a method where you can add the first and last numbers together, and then multiply by how many times that appears. Here, the sum of the first and last number is -11. In this sequence, it would appear ten times (since there are ten terms and the terms are used twice in every eleven). -11 * 5 is -55, so that means the answer to this question is -55. 
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The cost c (in dollars) for the care and maintenance of a horse and carriage is c= 15x 2000, where x is the number of rides? how
Semmy [17]
133.33
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3 0
3 years ago
What are the roots of the equation x2 - 5x + 6 = 0?
Alenkasestr [34]

The answer is

B. -2 and 3

Step-by-step explanation :

Given the expression

x²- 5x + 6 = 0

Firstly we need to find two numbers that when multiplied will give us the constant term 6, and when added will give us the 2nd term 5

These numbers are 3 and 2

Substituting 2x +3x for 5x

x²- (2x+3x)+ 6 = 0

x²-2x-3x+6=0

(x²-2x)-(3x+6)=0

Factoring we have

x(x-2)-3(x-2)=0

x-3=0, x-2=0

x=3, x= 2

7 0
3 years ago
It took the carriage 2.5 hours to travel 20 miles. H ow long will it take for the carriage to travel in 12 miles
Tomtit [17]
\bf \begin{array}{ccll}
hours&miles\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2.5&20\\
h&12
\end{array}\implies \cfrac{2.5}{h}=\cfrac{20}{12}\implies \cfrac{2.5\cdot 12}{20}=h
6 0
3 years ago
Check all of the ordered pairs that satisfy the equation below.y=2/5x
zvonat [6]

We are going to do this step by step:

Let's start with option A

A.

X = 25 and Y = 5/2

y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10

In this case, when X = 25 , then Y = 10 ,which is different to 5/2

B.

X = 14 , Y = 35

y=\frac{2}{5}\cdot14=\frac{28}{5}

In case, when X = 14, then Y = 28/5, which is different to 35

C.

X = 40 , Y = 24

y=\frac{2}{5}\cdot40=\frac{80}{5}=16

Similarly, in this case, when X = 40, then Y = 16, which is different to 24

D.

X = 10 , Y=4

y=\frac{2}{5}\cdot10=\frac{20}{5}=4

Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y

E.

X = 50 , Y = 20

y=\frac{2}{5}\cdot50=\frac{100}{5}=20

In this case, the values of Y are also the same.

F.

X = 30 , Y = 12

y=\frac{2}{5}\cdot30=\frac{60}{5}=12

Again, in this case, the values of Y are the same, so the pair satisfies the equation.

In conclusion: options D, E and F satisfy the equation

3 0
1 year ago
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