Answer and Step-by-step explanation:
we have the following data:
Point estimate = sample mean = \ bar x = 12.39
Population standard deviation = \ sigma = 3.7
Sample size = n = 177
a) the margin of error with a 90% confidence interval
α = 1 - 90%
alpha = 1 - 0.90 = 0.10
alpha / 2 = 0.05
Z \ alpha / 2 = Z0.05 = 1,645
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 1.645 * (3.7 / \ sqrt177)
Outcome:
E = 0.46
b) margin of error with a 99% confidence interval
α = 1-99%
alpha = 1 - 0.99 = 0.01
alpha / 2 = 0.005
Z \ alpha / 2 = Z0.005 = 2,576
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 2,576 * (3.7 / \ sqrt177)
Outcome:
E = 0.72
c) A larger confidence interval value will increase the margin of error.
$6469.177
I could be wrong but I'm pretty sure that is right.
Answer:
The median is 2
Step-by-step explanation:
Here, we want to get the median for the number of pencils
Firstly, we have to write out the numbers that form the box plot ; we have this as;
1,1,1,2,2,2,2,3,3,5
the median is sum of the 5th and 6th term divided by 2
The 5th term is 2
The 6th term is 2
So the median is;
(2 + 2)/2
= 4/2 = 2
<span>(2.0x10^4)(3.0x10^3)
= ( 2 x 3)( 10^4 x 10^3)
= 6 x 10^7
hope it helps</span>
The negative externalities must be present.
