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Marta_Voda [28]
3 years ago
9

Find the percent change from 30 to 6

Mathematics
1 answer:
nadezda [96]3 years ago
8 0

Answer:

-80.00%

Step-by-step explanation:

1) Find the difference between 30 and 6 as a number.

2) Divide the result from Step 1 by the starting number 30.

3) Multiply the result from Step 2 by 100 to get it in terms of percent.

The three steps above can be made into a formula. Thus, to find the percent change from 30 to 6, we use this formula:

((Y-X)/X)*100 = Percent Change

X is the starting number 30, and Y is the ending number 6 that it changed to. When we enter these numbers into the formula, we get:

((6-30)/30)*100 = -80.00%

Thus, the answer to the question "What is the Percent Change from 30 to 6?" is:

-80.00%

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Find the slope and the y-intercept of the line 6x+2y=5.
Alexeev081 [22]
The slope is -3 I’m not sure about the intercept
3 0
3 years ago
If x=2 ,y=12 and x=4,y=3,find n and k if y is inversely proportional to x and k is a constant
Setler [38]

question:

x=2 ,<em>y</em>=12 and x=4,y=3,find n and k if y is inversely proportional to x and k is a constant

answer:

k=12 x=3 n=4

explain:

that the answer because the question said find the k and x and n so I find them

8 0
2 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
In the drawing below , PQ is parallel to ST. Triangle is similar to triangle TSR.
Lapatulllka [165]
SR corresponds to PR
7 0
3 years ago
HELP ASAP 15 POINTS!!!<br> What is the solution to this equation?<br> 6(x-5)=4x+20
Andre45 [30]

Answer:

<h2><u><em>x = 25</em></u></h2>

Step-by-step explanation:

What is the solution to this equation?

6 * (x - 5) = 4x + 20

6x - 30 = 4x + 20

2x = 20 + 30

2x = 50

x = 50 : 2

x = 25

-------------------

check

6 * ( 25 - 5) = 4 * 25 + 20

6 * 20 = 100 + 20

120 = 120

the answer is good

3 0
2 years ago
Read 2 more answers
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