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denis-greek [22]
3 years ago
11

PLEASE HELP! urgent! Write the equation of a line in a slope-intercept form and standard form

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

y = \frac{3}{4}x -3 --- Slope intercept

4y - 3x =- 12 --- Standard form

Step-by-step explanation:

Given

The attached linear graph

Required

The equation

Select any two points on the line

(x_1,y_1) = (0,-3)

(x_2,y_2) = (4,0)

Next, calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

So, we have:

m = \frac{0 --3}{4 - 0}

m = \frac{3}{4}

The slope intercept is then calculated using:

y = m(x - x_1) + y_1

So, we have:

y = \frac{3}{4}(x - 0) -3

y = \frac{3}{4}(x) -3

y = \frac{3}{4}x -3

Multiply through bu 4

4y = 3x - 12

Subtract 3x from both sides

4y - 3x =- 12 --- Standard form

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