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3 years ago

Need help Choices 4 3 2 1

Mathematics

2 answers:

Volgvan3 years ago

8 0

Answer:

Step-by-step explanation:

-Dominant- [34]3 years ago

4 0

Answer:

Step-by-step explanation:

The amplitude is the maximum distance away from the middle of the wave. Here we can see that the middle of the wave is the x axis and the farthest point (largest difference between the y coordinate of the x-axis, or the line y = 0, and the wave) is 1 unit away.

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2 years ago

xialoli was estimating the difference between two positive numbers x and y (where x>y). First she rounded x up by a small amo

AleksandrR [38]

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This is an excellent question. Estimation is a powerful skill to have. People should always shop using estimates. Try it to see what happens.

x = 11.7 which rounds up to which we will call x1 and that is 12

y = 6.03 which round down to 6 which we will call y1 and that is 6

Now x - y = 5.67

If you do the rounded subtraction x1 - y1 = 12 - 6 = 6

The estimate is not zero. D is not correct.

There is enough information E is not the answer.

B is wrong, her estimate is larger than x - y

C is wrong the two subtractions are not equal.

A is correct and always will be no matter what numbers are chosen

A <<<< Answer

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2 years ago

Really need help guys!<br> Love you if you can solve them wiz steps!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

$x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\$

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

$b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}$

$c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16$

$d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6$

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1 year ago