Answer:
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Step-by-step explanwenfcbuwerhiducnuiadfvbhnwerbvijrifvuwefnovjndfihvnihmseubvniakjwrsdxuvgybqnaisefhcbatio347569874360532856923485723849527305873485693475gvtghb4rhnbthwesu8fhnviuryedbngjskuryufvsirhlbgfoiarlshfbvlkzrjnfer g bgergsjkrfvksnzekjvnzdijdfvn nzudflvhgiaejhgvaijrsnvipafrngfxpiuvjnzdfkv;lj zshdlvouhsrilgvjsrfnvfkjvbnfvkkjxfbnjxfbkjfxvbjlbfxkhjfbvhhxkjbcvkjnxfckvbjnzxfbvzhjkvcb ;xfhcjnvbjhkxfnv zxfjvhbdukjchvbfhdsbarbf vbousdjbgukyfbher,iyfhbvierygfhdyriudrkjdfijkcvx ncvxiu dbfedfiukjjakleriufhoriuthpiurhfbioerufuirtirhr8gujesriughirueghoisdrghiurjgoierdjgsoidrgj;sidfigjsdfiogjisdufgjidsfgjodfuhgjidfkgkohdflijvksdfbujlksdfjgndghiujnneuifjgknserujghdsfikugheridfjgnsiudfjgkdhrfgusfiusejrdfgiesrgjrshdfiughjdrhfogusdrghsdfjgfjgjseruhguaerkjsgesj.rhdfgiesbtldfhl.w,hetks;ifgkbjvidorstuljkfvnhse7izdyfhuxgcjudiflxhgnzdhoufhgfghskdhfgjkdsrfghjkfgsdjfghsjdfghsdfjghsdjghfjghfdjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjn:
Answer:
Dude the picture is really blurry
Step-by-step explanation:
Answer:
The frequency of the note a perfect fifth below C4 is;
B- 174.42 Hz
Step-by-step explanation:
Here we note that to get the "perfect fifth" of a musical note we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have
1.5 × Frequency of note Y = Frequency of C4
1.5 × Y = 261.63
Therefore, Y = 261.63/1.5 = 174.42 Hz.
Answer:
Step-by-step explanation:
perimeter of the figure = perimeter of the rectangle + perimeter of the semicircle
= 2(l+B) + 
r
= 2( 10+8) + 3.14 × 5
= 36 + 15.7
= 51.7
= 100 ( rounding off to nearest hundredth )
hope this helps
plz mark it as brailiest!!!!!!
Given the equation:
(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:
However, the student made a mistake when adding the numbers on the right side.
Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:
- Add their Absolute values (their values without the negative sign).
- Write the sum with the negative sign.
Then:
(b) The correct procedure is:
1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):
2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:
Hence, the answers are:
(a) The student made a mistake by adding the numbers -18 and -3:
(b) The value of "x" should be:
