The amount invested at 11% is $5,000
The amount invested in stock is $14,000
What is the net profit on both investments?
The profit of each investment is the rate of return or loss multiplied by the amount invested
Let us assume that x was invested at 11% and the remaining 19000-x was invested at a loss rate of 3%
net profit=(11%*x)+(19000-x)*-3%
net profit=130
130=(11%*x)+(19000-x)*-3%
130=0.11x-570+0.03x
130=0.14x-570
130+570=0.14x
700=0.14x
x=700/0.14
x=$5,000
Amount invested in stock=19000-x
Amount invested in stocks=19000-5000
Amount invested in stocks=$14,000
Find out more about combined investments on:brainly.com/question/2166053
#SPJ1
Answer:
The answer is "
".
Step-by-step explanation:
please find the complete question in the attached file.
![=\frac{1}{10} (\frac{x^3}{3})^{5}_{-5}\\\\=\frac{1}{30}[5^3+5^3]\\\\=\frac{2}{30}(125)\\\\=\frac{1}{15} \times 125\\\\=\frac{25}{3}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B10%7D%20%28%5Cfrac%7Bx%5E3%7D%7B3%7D%29%5E%7B5%7D_%7B-5%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B30%7D%5B5%5E3%2B5%5E3%5D%5C%5C%5C%5C%3D%5Cfrac%7B2%7D%7B30%7D%28125%29%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B15%7D%20%5Ctimes%20125%5C%5C%5C%5C%3D%5Cfrac%7B25%7D%7B3%7D)
Set up a system of equations.
0.10d + 0.25q = 39.25
d + q = 250
Where 'd' represents the number of dimes, and 'q' represents the number of quarters.
d + q = 250
Subtract 'q' to both sides:
d = -q + 250
Plug in '-q + 250' for 'd' in the 1st equation:
0.10(-q + 250) + 0.25q = 39.25
Distribute 0.10:
-0.10q + 25 + 0.25q = 39.25
Combine like terms:
0.15q + 25 = 39.25
Subtract 25 to both sides:
0.15q = 14.25
Divide 0.15 to both sides:
q = 95
Now plug this into any of the two equations to find 'd':
d + q = 250
d + 95 = 250
Subtract 95 to both sides:
d = 155
So there are 95 quarters and 155 dimes.
0.4 has 4 tenths
Look at 0.4 as 0.40
Divide the 40 by 10 and get 4
-Hope this helped!
Answer:8
Step-by-step explanation:
