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Mashcka [7]
3 years ago
10

Which expression is not equivalent to

Mathematics
2 answers:
Marina CMI [18]3 years ago
7 0

Answer: B

Step-by-step explanation:

Romashka [77]3 years ago
4 0

Answer:

B: 2x + 2 + x

Step-by-step explanation:

I just had this question and got it right

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Answer this with work! I am rank 2 <br><br><br> Distributive property2x - 4(+4) = 10(+4)?
GrogVix [38]
Use the method pemdas and you get x=28
7 0
3 years ago
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What is the slope of 4x+5y= -10
Aleonysh [2.5K]

Answer:

-\frac{4}{5}

Step-by-step explanation:

To find the slope, rearrange the equation to y=mx+b or y=mx+c.

4x+5y=-10

Subtract 4x from both sides:

5y=-10-4x

Divide 5 on both sides:

y=\frac{-10-4x}{5}

y=-\frac{4}{5} x-2

In the equation of y=mx+b/y=mx+c, m will be the slope.

Therefore, the slope is -\frac{4}{5}

6 0
3 years ago
4g + 3(-3 + 4g) = 1-g. Solve the equation. Can someone help me ASAP. I'm confused
Olegator [25]
4g+3(-3+4g)=1-g
Distribute the 3(-3+4g)
4g-9+12g=1-g
Add 4g and 12g
16g-9=1-1g
Add 1g and 16g (variables always have an invisible 1 in front)
17g-9=1
Add 9 and 1
17g=10
Divide both sides by 17 and the answer is g=10/17
5 0
3 years ago
james attached a diagonal brace across a rectangular frame that measures 6ft by 8ft what is the length of the diagonal brace
Bogdan [553]
To solve this you would use the pythagorean theorem since the brace is making the frame look like two right triangles. The theorem states that for a triangle with a right angle, A^2+B^2=C^2. A and B are the sides of the frame and C is the brace which is like the hypotenuse of the triangle. It doesn't matter which side is A or B so you can put 6 or 8 in place of either in the equation. 6^2+8^2=C^2. If you simplify this it equals 36+64=C^2, which then simplifies to 100=C^2. Then you take the square root of both sides (what number multiplied by itself = the number you are trying to get, in this case, 100). So then you get C=10 because 10x10=100. So the length of the diagonal brace is 10ft.
4 0
3 years ago
Implicit differentiation Please help
Anvisha [2.4K]

Answer:

y''(-1) =8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Quotient Rule: \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

<u>Step 2: Differentiate Pt. 1</u>

<em>Find 1st Derivative</em>

  1. Implicit Differentiation [Product Rule/Basic Power Rule]:                            -y - xy' - 2y' = 0
  2. [Algebra] Isolate <em>y'</em> terms:                                                                               -xy' - 2y' = y
  3. [Algebra] Factor <em>y'</em>:                                                                                       y'(-x - 2) = y
  4. [Algebra] Isolate <em>y'</em>:                                                                                         y' = \frac{y}{-x-2}
  5. [Algebra] Rewrite:                                                                                           y' = \frac{-y}{x+2}

<u>Step 3: Find </u><em><u>y</u></em>

  1. Define equation:                    -xy - 2y = -4
  2. Factor <em>y</em>:                                 y(-x - 2) = -4
  3. Isolate <em>y</em>:                                 y = \frac{-4}{-x-2}
  4. Simplify:                                 y = \frac{4}{x+2}

<u>Step 4: Rewrite 1st Derivative</u>

  1. [Algebra] Substitute in <em>y</em>:                                                                               y' = \frac{-\frac{4}{x+2} }{x+2}
  2. [Algebra] Simplify:                                                                                         y' = \frac{-4}{(x+2)^2}

<u>Step 5: Differentiate Pt. 2</u>

<em>Find 2nd Derivative</em>

  1. Differentiate [Quotient Rule/Basic Power Rule]:                                          y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}
  2. [Derivative] Simplify:                                                                                      y'' = \frac{8}{(x+2)^3}

<u>Step 6: Find Slope at Given Point</u>

  1. [Algebra] Substitute in <em>x</em>:                                                                               y''(-1) = \frac{8}{(-1+2)^3}
  2. [Algebra] Evaluate:                                                                                       y''(-1) =8
6 0
3 years ago
Read 2 more answers
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