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horrorfan [7]
3 years ago
6

Help me with this please

Mathematics
1 answer:
inessss [21]3 years ago
3 0

Answer:

115

Step-by-step explanation:

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What is the multiplicative rate of change of the function shown on the graph? Express your answer in decimal form. Round to the
allsm [11]
In linear models there is a constant additve rate of change. For example, in the equation y = mx + b, m is the constanta additivie rate of change.


In exponential models there is a constant multiplicative rate of change.


The function of the graph seems of the exponential type, so we can expect a constant multiplicative exponential rate.


We can test that using several pair of points.


The multiplicative rate of change is calcualted in this way:

 [f(a) / f(b) ] / (a - b)

Use the points given in the graph: (2, 12.5) , (1, 5) , (0, 2) , (-1, 0.8)

[12.5 / 5] / (2 - 1) = 2.5


[5 / 2] / (1 - 0) = 2.5


[2 / 0.8] / (0 - (-1) ) = 2.5


Then, do doubt, the answer is 2.5





6 0
3 years ago
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What is the first step you should take to solve the following expression: 17:4+ 22 – 12x33?
PolarNik [594]

Answer:

1/4 - 3 2/5 - (2 1/3 - 1/4) =

-157/30=

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≅ -5.2333333

Step-by-step explanation:

3 0
3 years ago
1. What values of a, b, and c would you use in the quadratic formula for the following equation?
kiruha [24]
Answer: See each part below.

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3) If you graph the equation, it will be above the x-axis. Therefore, it has no roots. Choice D

4) Choice A is correct. Use the coefficients: A = 4, B = 3, C = -10. Simply plug those into the quadratic equation and you will get -2 and 1.25.
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Tony heard that housing expenses should
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Multiply the month;y income by the percentage:

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He can spend $2,324 a month.

7 0
3 years ago
39 divide (2+1) - 2 x (4+1)
Anvisha [2.4K]

Answer:

8-2x I think

Step-by-step explanation:

You would first divide 39 by 3, ( 2 + 1 = 3) and get 13.

You would next take 5 away from 13 and get 8.

Then you have your answer, because you cannot simplify it more because both the numbers do not have the same variable.

8 0
3 years ago
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