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Natali [406]
3 years ago
5

ANSWER PLEASE...

Mathematics
2 answers:
Drupady [299]3 years ago
6 0

Answer:

All in ft

Mean: 28,235

Median: 28,208

Range: 1,245

Step-by-step explanation:

Mean is the sum of the elements divided by the number of elements.

(29035+28250+28208+27890+27790)/5 = 28235

Median is the element in the exact middle of the set (if there is an even number of elements, take the average of the two elements in the middle).

After rearranging the numbers, we can see 28208 is in the exact middle.

27790 27890 28208 28250 29035

Range is the difference between the smallest and largest number in the set.

29035-27790=1245

liraira [26]3 years ago
4 0

Answer: The median is 28208 the mean is 28234.6

Step-by-step explanation:

The mode is the number that is repeated the most there can be more than one mode.

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Step-by-step explanation:

The engineer can use a clinometer to measure the angle of elevation of the top of the tree. Let the height of the tree be represented by x, the she could determine the distance across the river, d, by applying the trigonometric function.

Tan θ = \frac{opposite}{adjacent}

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The sketch to the explanation is attached to this answer for more clarification.

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4) The path of a satellite orbiting the earth causes it to pass directly over two
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Answers:

  • Satellite is approximately <u>2446.43 km</u> from station A.
  • Satellite is approximately <u>2441.61 km</u> above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

  • AB = 60 km
  • AD = x
  • CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) .............  apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km  is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0
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