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3 years ago

Solve |x|=5 A{-5} B{5} C{-5,5}

Mathematics

2 answers:

vaieri [72.5K]3 years ago

5 0

Answer:

$x=-5\quad \mathrm{or}\quad \:x=5$

C is your answer

Step-by-step explanation:

$\left|x\right|=5\\\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a\\x=-5\quad \mathrm{or}\quad \:x=5$

ExtremeBDS [4]3 years ago

5 0

C is your answer
use absolute value

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3 years ago

In an arithmetic sequence, the nth term an is given by the formula an=a1+(n−1)d, where a1 is the first term and d is the commo

Dmitry_Shevchenko [17]

Answer:

$a_{10} = \frac{10}{65536}$

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

$a_{3} - a_{2} = a_{2} - a_{1}$

We have that:

$a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}$

$a_{3} - a_{2} = a_{2} - a_{1}$

$\frac{5}{2} - 10 = 10 - 40$

$\frac{-15}{2} \neq -30$

This is not an arithmetic sequence.

This sequence is geometric if:

$\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}$

$\frac{\frac{5}[2}}{10} = \frac{10}{40}$

$\frac{5}{20} = \frac{1}{4}$

$\frac{1}{4} = \frac{1}{4}$

This is a geometric sequence, in which:

The first term is 40, so $a_{1} = 40$

The common ratio is $\frac{1}{4}$ , so $r = \frac{1}{4}$ .

We have that:

$a_{n} = a_{1}*r^{n-1}$

The 10th term is $a_{10}$ . So:

$a_{10} = a_{1}*r^{9}$

$a_{10} = 40*(\frac{1}{4})^{9}$

$a_{10} = \frac{40}{262144}$

Simplifying by 4, we have:

$a_{10} = \frac{10}{65536}$

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3 years ago

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Answer:

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Step-by-step explanation:

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Read 2 more answers

Y and x have a proportional relationship and y=9 when x=2 what is the value of y when x=3

Paladinen [302]

If they are proportional, then y/x should always be the same.

So 9/2= 4.5

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4.5 = y/3

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