Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Assuming we’re talking about a cylinder, whose volume formula is V = pi r^2 h…
It will have a greater effect to change a variable’s value that has a greater power on it.
Changing h from 1 to 2 doubles the volume.
Changing r from 1 to 4 quadruples the volume, because 1^2 = 1 and 2^2 = 4. The effect of the change on r is amplified by the power.
Answer:
1152 or 1200 is the answer I don’t know which one though.
Step-by-step explanation:
<em><u>should be G : y=2x+1</u></em>
Answer:
B) 2
C) y = 2x
Step-by-step explanation:
Part B
Constant is 2 because in order to get x to the value of y, you must multiply by 2.
Part C
y = 2x
