6th one....pls help me out

Mathematics

1 answer:

zmey [24]2 years ago

4 0

Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.

You might be interested in

Simplify<br> a(cube)-1000b(cube)<br> 64a(cube)-125b(cube)

Elanso [62]

The simplification of a³ - 1000b³ and 64a³ - 125b³ is (a - 10b) × (a² + 10ab + 100b²) and 4a - 5b) • (16a² + 20ab + 25b²) respectively.

<h3>Simplification</h3>

Question 1: a³ - 1000b³

a³ - b³

= (a-b) × (a² +ab +b²)

1000 is the cube of 10
a³ is the cube of a¹
b³ is the cube of b¹

So,

(a - 10b) × (a² + 10ab + 100b²)

Question 2: 64a³ - 125b³

a³ - b³

= (a-b) × (a² +ab +b²)

64 is the cube of 4
125 is the cube of 5
a³ is the cube of a¹
b³ is the cube of b¹

So,

(4a - 5b) • (16a² + 20ab + 25b²)

Learn more about simplification:

brainly.com/question/723406

#SPJ1

8 0

1 year ago

Another plan to secure the roller coaster involves placing two concrete struts on either side of the center of the leg of the ro

skelet666 [1.2K]

Answer:

The beam should be placed 8 feet from the center.

Step-by-step explanation:

The struts are y = √(x + 8) and y = √(x − 4). The struts are 2 feet apart at the location of the beam:

√(x + 8) − √(x − 4) = 2

Solving:

√(x + 8) = 2 + √(x − 4)

x + 8 = 4 + 4√(x − 4) + x − 4

8 = 4√(x − 4)

2 = √(x − 4)

x − 4 = 4

x = 8

8 0

2 years ago

Compute $\sqrt{25^2-7^2}$.

EastWind [94]

Answer:

Step-by-step explanation:

$\sqrt{25^2-7^2}\\\\=\sqrt{(25-7)(25+7)}\\\\=\sqrt{18(32)}\\\\=\sqrt{9*2*2^5}\\\\=\sqrt{3^2\cdot 2^6}\\\\=\sqrt{(3\cdot2^3)^2}\\\\=3\cdot2^3\\\\=3\cdot8\\\\=24$