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4 years ago

Find the area 19 in 12.6 in 29.2 in

1 answer:

6 0

B = 29.2 in.
<span>b= 19 in. </span>
<span>h = 12.6 in. </span>

<span>A= (29.2 + 19)*12.6/2 = 303.66 in^2 </span>

<span>Answer: 303.66 in.2

-Hope I helped.</span>

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What is 10+10<br> and what is 4+5

seropon [69]

20 and 9 is the answer

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3 years ago

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Common denominator of 3, 4, 5.

gtnhenbr [62]

Answer:

The LCM of 3,4,5 3 , 4 , 5 is 2⋅2⋅3⋅5=60 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60 .

Step-by-step explanation:

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3 years ago

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A circle's circumference is approximately 44 cm.

Sav [38]

<h3>Answers</h3><h3>diameter = 14</h3><h3>radius = 7</h3><h3>area = 154</h3>

these are all approximate

======================================

Explanation:

C = pi*d is the formula for the circumference. We know that C = 44 approximately, so,

C = pi*d

d = C/pi

d = 44/3.14

d = 14.01 approximately

d = 14 also approximate

take half of this to get the radius

r = d/2 = 14/2 = 7

Then use this radius to find the circle's area

A = pi*r^2

A = 3.14*7^2

A = 153.86

A = 154 rounding to the nearest whole number

7 0

3 years ago

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successi

My name is Ann [436]

Answer:

option C

c. least: $101

greatest: $1001

Step-by-step explanation:

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.

Sum of 10 prizes = 5510

100 is the difference. there is a common difference d=100

So its a arithmetic sequence

the sum formula for arithmetic sequence is

$S_n = \frac{n}{2}(2a_1 +(n-1)d)$

Sn = 5510, n=10 n d= 100 we need to find out first term a1

$5510 = \frac{10}{2}(2a_1 +(10-1)100)$

5510 = 5 (2a1 + 900)

5510 = 10a1 + 4500

Subtract 4500 on both sides

1010= 10a1

divide by 10 on both sides

a1 = 101

so first term that is least term is 101

To find out greatest term we use formula

$a_n = a_1 + (n-1) d$

a(10) = 101 + (10-1)100

= 101 + 900= 1001

greatest is 1001

4 0

4 years ago

Use cylindrical coordinates. Find the volume of the solid that lies within both the cylinder x2 + y2 = 25 and the sphere x2 + y2

Inessa05 [86]

Answer:

Step-by-step explanation:

we are asked to find the volume of solid that lies within both the cylinder

$x^2 + y^2 = 25$

and

the sphere $x^2 + y^2 + z^2 = 49.$

Conversion from rectangular to cylindrical is

$x=rcost\\y = rsint\\z=z$

|J| =r

In cylindrical coordinates the volume is bounded by the cylinder r=5 and

$r^2+z^2 =49$

Hence we can write volume as

$\int \int \int dxdydz\\=\\\int _0^5 \int_0^{2\pi} \int_{-\sqrt{49-r^2} } ^{\sqrt{49-r^2} rdzdtdr\\= 2\pi \int _0^5 (2\sqrt{49-r^2} rdr\\=4\pi (-(49-r^2) (2/3)\\= \frac{4\pi}{3} (343-48\sqrt{6} )$

6 0

3 years ago