<u>EXPLANATION</u><u>:</u>
Given set A = { 1,2,3}
n(A) = 3
Let the n(B) be n
Total number of relations from A to B = 2^(3×n) =2^3n
According to the given problem
Total relations are = 512
⇛2^3n = 512
⇛2^3n = 2⁹
If bases are equal then exponents must be equal
⇛3n = 9
⇛n = 9/3
⇛n = 3
<h3>So, Number of elements in the set B = 3</h3>
Answer:
9
Step-by-step explanation:
18 + 18 is like 36 divied by 2 is 18 then dvide that by two is 9 so 9
8 can go into 71 seven times
9=5 -y/3
-5
3=-y/3
cross multiply
1=-y
y=-1
