Pls show work for this math problem 100%
2 answers:
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Answer:
Step-by-step explanation:
We are given the square root function below:
Recall that domain is the set of all x-values and that a number inside the square root cannot be negative.
From the given square root function above, substituting x >= 2 gives a positive output. But if we substitute x < 2, evaluating the numbers inside result in negative number in the square root which does not exist in Real Number.
Hence,
And thus, the domain is
Since if x < a, the output would become an imaginary number.
From the given function,
From the form of sqrt(x-a) where domain is a-term which is 2.
Since a = 2, and thus