1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alenkinab [10]
3 years ago
14

Jessica Barth 15 pieces of ribbon each piece of ribbon was 2.25 yards long what is the total amount of ribbon Jessica bu Jessica

bought 15 pieces of ribbon each piece of ribbon was 2.25 yards long what is the total amount of ribbon Jessica BOUGHT
Mathematics
1 answer:
Flauer [41]3 years ago
6 0
The answer is 3.375
You might be interested in
The least common denominator of 1/2, 1/6, and 1/9 is:
solmaris [256]

Answer:

18

Step-by-step explanation:

Find the factors of each denominator

2 = 1*2

6 = 2*3

9 = 3*3

The least common multiple is

2*3*3 = 18

The least common denominator is 18

4 0
3 years ago
Read 2 more answers
Change from rectangular to spherical coordinates. (let ≥ 0, 0 ≤ ≤ 2, and 0 ≤ ≤. ) (a) (5, 5 3 , 10 3 )
Nikolay [14]

The spherical coordinate that is converted from the given rectangular coordinate is (12.62, 46.67°, 35.3°).

Here, the given rectangular coordinate is (5, 5.3, 10.3).

Therefore, the value of 'x' is 5, the value of 'y' is 5.3 and the value of 'z' is 10.3.

We can convert the rectangular coordinate (x, y, z) into spherical coordinate (ρ, θ, Φ) by the below mentioned method.

We know, ρ² = (x²+y²+z²)

Therefore, ρ

= √(x²+y²+z²)

= √[(5)²+(5.3)²+(10.3)²]

= √(25+28.09+106.09)

= √(159.18)

= 12.62

Again, tan θ = (y/x)

Therefore, θ = tan⁻¹(y/x) = tan⁻¹(5.3/5) = tan⁻¹(1.06) = 46.67°

Similarly, cos Φ = (z/ρ)

Therefore, Φ = cos⁻¹(z/ρ) = cos⁻¹(10.3/12.62) = cos⁻¹(0.816) = 35.3°

Here, the spherical coordinate is (ρ, θ, Φ).

Therefore, the required spherical coordinate for the given rectangular coordinate is (12.62, 46.67°, 35.3°).

Learn more about the conversion of a rectangular coordinate to a spherical coordinate here: brainly.com/question/17185505

#SPJ4

8 0
2 years ago
Determine the type of boundary line and shading for the graph of the inequality 5x + y greater than or equal to −10. (5 points)
goldfiish [28.3K]

The correct answer is d. Solid line with shading on the side that includes the origin

We can tell this for two reasons. Firstly, since it is "greater than or equal to" we use a solid line. If it were just "greater than" than we would have used a dotted line.

Secondly, to tell if the origin should be shaded is by plugging in (0,0) and seeing if it is a true statement. If it is true, it is shaded.

5x + y ≥ -10

5(0) + 0 ≥ -10

0 + 0 ≥ -10

0 ≥ -10 (TRUE)

7 0
4 years ago
Please show work thank you math experts
MakcuM [25]

Answer:

See below

Step-by-step explanation:

1) The distribution is skewed left because the majority of the data lies in the left tail.

2) Given what we answered in #1, the mean is going to be the closest of the three measures of central tendency, with the median behind the mean, and the mode behind the median.

3) An outlier is a piece of data that is furthest away from of a set of observed data.

3 0
2 years ago
Sum of the fractions as a mixed numbers<br><br>2 5/6 + 4 3/6 =​
snow_tiger [21]
7 and 1/3 hope this helps
6 0
3 years ago
Other questions:
  • U=10y/3x<br><br>Solve for x​
    8·1 answer
  • The number of lines formed by 4 points, no three of which are collinear, is ____. A.5 B.4 C.6 D.3
    10·1 answer
  • 2+x-(3-z); use x=6, and z=1​
    6·2 answers
  • What is the domain of the profit function P=6t+10s?
    5·2 answers
  • 3) The height of an object that is thrown straight up from a height of 6 feet
    5·1 answer
  • Help identify the mapping diagram.
    9·2 answers
  • -5r + 2 - 7 + 3k use r= 3 and k=6
    15·2 answers
  • Give the degree of each polynomial
    12·2 answers
  • Find the measure of angle 4 AND...… angle 7
    6·1 answer
  • Will give brainliest
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!