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ololo11 [35]
2 years ago
8

Corey tosses 4 fair coins. What is the probability that all four coins will land tails up?

Mathematics
2 answers:
Fed [463]2 years ago
5 0

Answer:

4/8

Step-by-step explanation:

IgorLugansk [536]2 years ago
4 0
I am almost 100 percent sure it’s 4/8
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What is 238/5 ans a mixed number
ankoles [38]
Divide 235/5 so 47 check by doing 47 times 5 it checks so the answer is 47
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3 years ago
Find the percent of decrease if 110 is decreased to 88 A) 125% B)80% C)20%
stich3 [128]

Hey there! I'm happy to help!

We have 110 minus a certain percent of 110 equals 88. Let's call this percent p and solve.

110-110p=88

We subtract 110 from both sides.

-110p=-22

We divide both sides by 110.

p=0.2

Therefore, the percent decrease is C) 20%.

Have a wonderful day! :D

4 0
3 years ago
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Find the value of f(5) for the function.<br><br> F(x)=6+3x
GuDViN [60]

Answer:

21

Explanation:

To solve this problem, you substitute in the 5 for the x creating this equation: f(5)=6+3(5).

f(5)=15+6

f(5)=21

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2 years ago
What is the area of the shaded part of the circle? you don't have to explain if you don't want to.
dsp73
12.56cm squared is the area of the shaded part of the circle.
6 0
3 years ago
A floppy disc can store 1440000 bytes of data
max2010maxim [7]

Answer:

1440000 = 1.44\times 10^{6}

We need approximately 1667 floppy disc to store 2.4\times 10^9 bytes of data.      

Step-by-step explanation:

We are given the following information in the question:

A floppy disc can store 1440000 bytes of data.

We have to convert  1440000 in a standard form.      

Standard Form:

  • Standard form is a way of writing down very large or very small numbers easily.
  • It helps us to express large numbers in powers of 10

The standard form can be written as:

1440000 = 1.44\times 10^{6}

We have positive power of 10 because we have to move to the right of the decimal point.

A hard disc can store 2.4\times 10^9 bytes of data.

Number of floppy disks needed to store the 2.4\times 10^9 bytes of data =

\displaystyle\frac{\text{Data Stored}}{\text{Data store by 1 floppy disk}}\\\\= \frac{2.4\times 10^9}{1.44\times 10^6} = 1.66667\times 10^{(9-6)} = 1.66667\times 1000 = 1666.67 \approx 1667

Thus, we need approximately 1667 floppy disc to store 2.4\times 10^9 bytes of data.

3 0
3 years ago
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