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Soloha48 [4]
3 years ago
12

frac{8 + \sqrt{2} i}{3 - 4i} " alt=" \frac{8 + \sqrt{2} i}{3 - 4i} " align="absmiddle" class="latex-formula">
please help me

​
Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0
Easy...
the root of 2 Is approximately 1.4 to 12343910 to the power of five to the six of the 7×3 which equals to five and then you have to divided by 3.3-40+ -1 so you had to do 8+1.4239 110 but she was to 9.1 9.423910 and then divided by -1 which to your power you get your mom God he
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PLEASE HELP!!!
baherus [9]

Answer:

is 26

Step-by-step explanation:

because i said

7 0
3 years ago
Point P is the center of the circle below. What is the exact area
igor_vitrenko [27]

Answer:

Area =192\pi

Step-by-step explanation:

Given

\theta = 120^o

r =24

Required

The area of the shaded sector

This is calculated as:

Area =\frac{\theta}{360} * \pi r^2

This gives

Area =\frac{!20}{360} * \pi *24^2

Area =\frac{1}{3} * \pi *576

Area =\pi *192

Area =192\pi

6 0
3 years ago
(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each
Leviafan [203]

Following are the solution parts for the given question:

For question A:

\to (n) = 16

\to (\bar{X}) = 410

\to (\sigma) = 40

In the given question, we calculate 90\% of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}

\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\

Using the t table we calculate t_{ \frac{\alpha}{2}} = 1.753  When 90\% of the confidence interval:

\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53

So 90\% confidence interval for the mean weight of shipped homemade candies is between 392.47\ \ and\ \ 427.53.

For question B:

\to (n) = 500

\to (X) = 155

\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31

Here we need to calculate 90\% confidence interval for the true proportion of all college students who own a car which can be calculated as

\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}

\to C.I= 0.90

\to (\alpha) = 0.10

\to \frac{\alpha}{2} = 0.05

Using the Z-table we found Z_{\frac{\alpha}{2}} = 1.645

therefore 90\% the confidence interval for the genuine proportion of college students who possess a car is

\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344

So 90\% the confidence interval for the genuine proportion of college students who possess a car is between 0.28 \ and\ 0.34.

For question C:

  • In question A, We are  90\% certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
  • In question B, We are  90\% positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:  

brainly.in/question/16329412

7 0
2 years ago
There were 27,000 people at a ball game in Los Angeles. The day's receipts were $204,000. How many people paid $13 for reserved
Studentka2010 [4]
21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000
5 0
3 years ago
What’s the mean of 3 32 36 30 33 36
Daniel [21]

Answer:

Mean = 28.33

Step-by-step explanation:

Comment

You need two inputs. The first is the sum of the numbers and the second is the number of entries in the data.

Givens

Sum = 3 +  32 +   36 +   30 +   33 +   36

Number of entries = 6

Solution

Sum = 170

Mean = sum / number of enteries

Mean = 170 / 6

Mean = 28.33

4 0
1 year ago
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