<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B8%20%2B%20%20%5Csqrt%7B2%7D%20i%7D%7B3%20-%204i%7D%20" id="TexFormula1" title=" \

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3 years ago

frac{8 + \sqrt{2} i}{3 - 4i} " alt=" \frac{8 + \sqrt{2} i}{3 - 4i} " align="absmiddle" class="latex-formula">
please help me

Mathematics

1 answer:

Alexus [3.1K]3 years ago

5 0

Easy...
the root of 2 Is approximately 1.4 to 12343910 to the power of five to the six of the 7×3 which equals to five and then you have to divided by 3.3-40+ -1 so you had to do 8+1.4239 110 but she was to 9.1 9.423910 and then divided by -1 which to your power you get your mom God he

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PLEASE HELP!!!

baherus [9]

Answer:

is 26

Step-by-step explanation:

because i said

7 0

3 years ago

Point P is the center of the circle below. What is the exact area

igor_vitrenko [27]

Answer:

$Area =192\pi$

Step-by-step explanation:

Given

$\theta = 120^o$

$r =24$

Required

The area of the shaded sector

This is calculated as:

$Area =\frac{\theta}{360} * \pi r^2$

This gives

$Area =\frac{!20}{360} * \pi *24^2$

$Area =\frac{1}{3} * \pi *576$

$Area =\pi *192$

$Area =192\pi$

6 0

3 years ago

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

2 years ago

There were 27,000 people at a ball game in Los Angeles. The day's receipts were $204,000. How many people paid $13 for reserved

Studentka2010 [4]

21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000

5 0

3 years ago

What’s the mean of 3 32 36 30 33 36

Daniel [21]

Answer:

Mean = 28.33

Step-by-step explanation:

Comment

You need two inputs. The first is the sum of the numbers and the second is the number of entries in the data.

Givens

Sum = 3 + 32 + 36 + 30 + 33 + 36

Number of entries = 6

Solution

Sum = 170

Mean = sum / number of enteries

Mean = 170 / 6

Mean = 28.33

4 0

1 year ago