Hi there!
∠C = 40° and triangle ABC is isosceles, therefore:
∠C = ∠A = 40°
Angles in a triangle sum up to 180°, so:
180 = 40 + 40 + ∠A
180 = 80 + ∠A
100 = ∠A
Thus, arc CB has a measure of 100°.
Answer:
the answer is 13.5
Step-by-step explanation:
A=105
B=4
C=7
so you just plug in using the trigonometric formula for area which in this case would be
1/2(4)(7)sin(105)
then you just type that into a graphing calculator (make sure its set to degrees) then you get 13.52 which would be 13.5 rounded.
Dy/dx = dy/dt * dt/dx
xy = 4
y + x(dy/dx) = 0 by implicit differentiation.
x(dy/dx) = -y
dy/dx = -y/x
<span>dy/dx = dy/dt * dt/dx dy/dt = -2
</span>
<span>-y/x = -2 * dt/dx
</span>
y/(2x) = dt/dx
dt/dx = y/(2x)
dx/dt = 2x/y
When x = -3, xy = 4, y = 4/x = 4/-3 = -4/3
dx/dt = 2*-3/(-4/3) = -6 *-3/4 = 18/4 = 9/2 = 4.5
dx/dt = 4.5
Answer:(x+1)(x+14)
Step-by-step explanation:
