All categories

3 years ago

Please help, thanks!

Mathematics

1 answer:

Mamont248 [21]3 years ago

7 0

((-4x^3)(y^4))^-3
--------------------------
(2xy^4)^-4
16x^4y^16
=------------------------
-64x^9y^12
-16y^4
=------------------------
64x^5
-y
=------------------------
4x^5

So the final answer is:

-y^4
-------
4x^5

(Btw if "^" is in front of a number, that means it is an exponent, so when your writing this on paper, just write it as a regular exponent without the "^". I had to do that since I'm on a computer.)

Hopefully this was helpful in some way.

You might be interested in

5/8 brainliest im giving if u get it right :D

blondinia [14]

Well basically if they lost 8 points and gained 6, they have -2 points.

3 0

2 years ago

Read 2 more answers

Solve the equation: 16 = 2x - 6

Tom [10]

the answer 11

Step-by-step explanation:

6+16=22

22÷2=11

6 0

2 years ago

Read 2 more answers

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

PLEASE HELP ASAP THANK YOU

Nadya [2.5K]

<span>Simplifying 2x + 18y = 36 Solving 2x + 18y = 36 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-18y' to each side of the equation. 2x + 18y + -18y = 36 + -18y Combine like terms: 18y + -18y = 0 2x + 0 = 36 + -18y 2x = 36 + -18y Divide each side by '2'. x = 18 + -9y Simplifying x = 18 + -9y</span>

3 0

2 years ago

According to the south carolina department of mental health web site, for every 200 u.s. women, the average number who suffer fr

cupoosta [38]

3 are expected to have the condition.

The expected value is the found by multiplying the probability by the number in the sample:

(1/200)×600
= (1/200)×(600/1)
= (1×600)/(200×1)
= 600/200 = 3

3 0

2 years ago