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3 years ago

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Determine x when y=144?

1 answer:

Bad White [126]3 years ago

8 0

Do you have an equation or function or formula?

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please help me this due today by 3:00. Ronda won 40 super bouncy balls playing skeeball at her school’s game night. Later, she g

emmasim [6.3K]

Step-by-step explanation:

Well, 40 - 8 = 32, since she had 8 remaining. Then divide 32 by 2, since she gave 2 to each of her friends. Therefore, she has 16 friends.

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WHAT IS THE RELATIONSHIP BETWEEN THE ANGLE OF ELEVATION AND THE ANGLE OF DEPRESSION? GIVE AN EXAMPLE OF AN APPLICATION USING THE

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Angles of Elevation and Depression are used in measuring heights and distances in trigonometric applications using right triangles. These angles are made when we look up or down to view objects. Devices are available to measure angles of elevation and depression. These measured angles can be used in measuring heights and distance which are either tedious or impractical to measure, by modelling the situation into right triangles

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3 years ago

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What is 7 4/10 -1 1/3

Goryan [66]

The answer is 6 and 1/15.

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Please help don't guess

12345 [234]

So, just divide:

52.50 / 6 = 8.75

This means that she earns $8.75 an hour.

If this is her hourly salary, then multiply 8.75 x 11

8.75 x 11 = 96.25

So, if Paula works for 11 hours, she will earn $96.25!

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You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu

aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to $180^{o}$ .

Let the exterior angle be represented by $x^{o}$ , and the three interior angles of the triangle be represented by $a^{o}$ , $b^{o}$ and $c^{o}$ .

Assume that the vertex angle $c^{o}$ is the linear pair to the exterior angle $x^{o}$ .

i.e $x^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles on a straight line)

Thus,

i. $a^{o}$ + $b^{o}$ = $x^{o}$ (sum of two opposite interior angles is equal to an exterior angle)

⇒ $a^{o}$ = $x^{o}$ - $b^{o}$

Also,

$b^{o}$ = $x^{o}$ - $a^{o}$

But,

$a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

⇒ $c^{o}$ = $180^{o}$ - ( $a^{o}$ + $b^{o}$ )

and

$a^{o}$ + $b^{o}$ = $180^{o}$ - $c^{o}$

ii. $a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

$a^{o}$ = $180^{o}$ - ( $b^{o}$ + $c^{o}$ )

Also,

$a^{o}$ + $b^{o}$ = $x^{o}$

⇒ $b^{o}$ = $x^{o}$ - $a^{o}$

$c^{o}$ = $180^{o}$ - $x^{o}$

8 0

3 years ago