Write the equation of the line with slope m=1/3 through the point (6,−2). Then, sketch a graph of the line.Please be sure to sca
1 answer:
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Answer:
y +2 = (1/3)(x -6)
Step-by-step explanation:
When given a point and a slope, it is convenient to use the point-slope form of the equation for a line.
y -k = m(x -h) . . . . . line with slope m through point (h, k)
For your point and slope, this is ...
y +2 = 1/3(x -6)
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The slope of 1/3 means the graph has a "rise" of 1 for each "run" of 3:
slope = m = rise/run = 1/3
A graph of it is attached.
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Answer:
The required point is P(-7,) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,)
Note: Figure show equation of line red line and point P as blue dot.
