Let student tickets be s and adult tickets be a. The number of tickets sold of both adult and student then is s + a = 396. If each student ticket costs $3, then we represent the money equation by tacking the dollar amount onto the ticket. 3s is the cost of one student ticket. 4a is the cost of an adult ticket. The total money from the sales of both is 4a + 3s = 1385. We now have a system of equations we can solve for a and s. If s+a=396, then s = 396-a. We will sub that into the second equation to get 4a + 3(396-a) = 1385. Distributing we have 4a+1188-3a=1385. a = 197. That means there were 197 adult tickets sold. If s + a = 396, then s + 197 = 396 and s = 199. 197 adult tickets and 199 student tickets. There you go!
The ball will just about pass because...
you need to find the percentage that the ball bounced back so you would need to do 6 ÷ 4.1 which is 0.683... Then to find the percentage you would multiply the answer by 100 so: 0.68333×100, which equals 68.333%. This means that the ball will pass the inspection as it scores between 68% and 75%.
Answer:
26
Step-by-step explanation:
If each row has an equal number of trees, you would divide the total number of trees by the number of rows. 858/33 is 26
Answer:
Everything
Step-by-step explanation:
We can keep every things in the blank boxes.
I think it’s gonna be 6 adults for every 42 students not really sure so sorry if I got it wrong
