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3 years ago

5 points

Mathematics

2 answers:

Alinara [238K]3 years ago

8 0

C negative numbers are always last.

Leno4ka [110]3 years ago

8 0

Answer:

C. -35, -17, 2, 16, 21

The larger the NEGATIVE, the least it'll be. Positive number are always greater than any negative number.

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Solve the equation: 16 = 2x - 6

Tom [10]

the answer 11

Step-by-step explanation:

6+16=22

22÷2=11

6 0

3 years ago

Read 2 more answers

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.02}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2$

$n = 2401$

The minimum sample size is 2401.

4 0

3 years ago

Como resuelvo 2x +8x.4x

Alex_Xolod [135]

Honestly photo math works for everything

7 0

3 years ago

ALGEBRA HELP PLEASE!!!! I DO NOT UNDERSTAND <br> Question: What is the range of this function?

Olegator [25]

Answer is D {-8, -3, 5, 7 }

hope it helps

8 0

3 years ago

The regular price rounded to the nearest cent

Daniel [21]

Answer:

$189.43

Step-by-step explanation:

To find the original price, write a proportion. In your proportion, write one ration that has sale price over original price. The other ratio should be written with the corresponding percent values. Since the sale price is 65% off then you paid 35% of the regular the price. The proportion should be:

$\frac{66.30}{x}= \frac{35}{100}$

To solve cross multiply numerator and denominator of each fraction.

66.30(100) = x(35)

6630 = 35x

189.43 = x

This means the regular price is $189.43.

3 0

3 years ago