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2 years ago

5 points

Mathematics

2 answers:

Alinara [238K]2 years ago

8 0

C negative numbers are always last.

Leno4ka [110]2 years ago

8 0

Answer:

C. -35, -17, 2, 16, 21

The larger the NEGATIVE, the least it'll be. Positive number are always greater than any negative number.

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Please someone give me an actual answer.

barxatty [35]

Answer:

option 2

Step-by-step explanation:

3 0

3 years ago

Please help yall I gotta pass this test

Stella [2.4K]

Answer:

12.05

is the answer I think

7 0

2 years ago

Solve the following system of equations.<br> 2x+y = 3<br> x=2y – 1<br> x=<br> y=

qaws [65]

Answer:

y=1 x=1

Step-by-step explanation:

2x + y = 3

x = 2y - 1

It looks like I could substitute the x=2y-1. Into 2x+y=3

2(2y-1)+y=3

4y-2+y=3

5y=5

y=1

x=2(1)-1

x=1

4 0

3 years ago

(Q7) Determine the graph of the polar equation r = 12/6+4 cos theta.

masya89 [10]

ANSWER

b.

EXPLANATION

The given polar equation is,

$r = \frac{12}{6 + 4 \cos( \theta) }$

Cross multiply to get,

$r(6 + 4 \cos( \theta) ) = 12$

$6r + 4r\cos( \theta) ) = 12$

Substitute,

$r\cos( \theta) = x$

and

$r = \sqrt{ {x}^{2} + {y}^{2} }$

$6 \sqrt{ {x}^{2} + {y}^{2} } + 4x = 12$

$3\sqrt{ {x}^{2} + {y}^{2} } + 2x = 6$

$3\sqrt{ {x}^{2} + {y}^{2} } = 4 - 2x$

$9({x}^{2} + {y}^{2}) =( 4 - 2x ) ^{2}$

$9{x}^{2} + 9 {y}^{2} =16 - 16x + 4x ^{2}$

$5{x}^{2} + 9 {y}^{2} + 16x = 16$

This is an ellipse whose center is shifted to the left with orientation on the x-axis

The correct choice is B.

8 0

3 years ago

Find the solution of the differential equation that satisfies the given initial condition. dy/dx = xe^y, y(0) = 0

Anna [14]

$\dfrac{\mathrm dy}{\mathrm dx}=xe^y$
$e^{-y}\,\mathrm dy=x\,\mathrm dx$
$-e^{-y}=\dfrac{x^2}2+C$

$y(0)=0$
$\implies-1=C$
$\implies -e^{-y}=\dfrac{x^2}2-1$
$e^{-y}=1-\dfrac{x^2}2$
$-y=\ln\left(1-\dfrac{x^2}2\right)$
$y=-\ln\left(1-\dfrac{x^2}2\right)$

3 0

2 years ago