199•25%=49.75
49.75+199=248.75
248.75•7.5%=18.65625
18.65625+248.75=267.40625
therefore the answer is $248.41
Hey i hope my answer is helpful i did in my head so im sorry if its wrong−13 13/35
Step-by-step explanation:
6:36 = 6/36 = 1/6
3:18 = 3/18 = 1/6
therefore this ratios are equivalents...
<em><u>hope </u></em><em><u>this</u></em><em><u> </u></em><em><u>answer </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care!</u></em>
The correct question is:
Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)
Answer:
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
Step-by-step explanation:
We need to verify that
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
We differentiate
x = c1e^(-t) + c2e^(3t)
twice in succession, and substitute the values of x, x', and x'' into the differential equation
x''- 2x' - 3x = 0
and see if it is satisfied.
Let us do that.
x = c1e^(-t) + c2e^(3t)
x' = -c1e^(-t) + 3c2e^(3t)
x'' = c1e^(-t) + 9c2e^(3t)
Now,
x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]
= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)
= 0
Therefore, the differential equation is satisfied, and hence, x is a solution.
(The second one)
Noah ran 8.67 miles in 1 hour and 20 minutes
If we convert the fraction to a decimal (for the miles part) we get 8.67 or 8 2/3 miles.
If 1/3 of an hour is 20 minutes, and an hour is 60 minutes, we add 20 4 times, which gets us to 80, which is 20 past an hour.
