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aksik [14]
2 years ago
15

5 points

Mathematics
2 answers:
Alinara [238K]2 years ago
8 0
C negative numbers are always last.
Leno4ka [110]2 years ago
8 0

Answer:

C. -35, -17, 2, 16, 21

The larger the NEGATIVE, the least it'll be. Positive number are always greater than any negative number.

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Please someone give me an actual answer.​
barxatty [35]

Answer:

option 2

Step-by-step explanation:

3 0
3 years ago
Please help yall I gotta pass this test
Stella [2.4K]

Answer:

12.05

is the answer I think

7 0
2 years ago
Solve the following system of equations.<br> 2x+y = 3<br> x=2y – 1<br> x=<br> y=
qaws [65]

Answer:

y=1    x=1

Step-by-step explanation:

2x + y = 3

x = 2y - 1  

.

It looks like I could substitute the x=2y-1. Into 2x+y=3

2(2y-1)+y=3

4y-2+y=3

5y=5

y=1

x=2(1)-1

x=1

4 0
3 years ago
(Q7) Determine the graph of the polar equation r = 12/6+4 cos theta.
masya89 [10]
ANSWER

b.

EXPLANATION

The given polar equation is,

r = \frac{12}{6 + 4 \cos( \theta) }

Cross multiply to get,

r(6 + 4 \cos( \theta) ) = 12

6r + 4r\cos( \theta) ) = 12

Substitute,

r\cos( \theta) = x

and

r = \sqrt{ {x}^{2} + {y}^{2} }

6 \sqrt{ {x}^{2} + {y}^{2} } + 4x = 12

3\sqrt{ {x}^{2} + {y}^{2} } + 2x = 6

3\sqrt{ {x}^{2} + {y}^{2} } = 4 - 2x

9({x}^{2} + {y}^{2}) =( 4 - 2x ) ^{2}

9{x}^{2} + 9 {y}^{2} =16 - 16x + 4x ^{2}

5{x}^{2} + 9 {y}^{2} + 16x = 16

This is an ellipse whose center is shifted to the left with orientation on the x-axis

The correct choice is B.

8 0
3 years ago
Find the solution of the differential equation that satisfies the given initial condition. dy/dx = xe^y, y(0) = 0
Anna [14]
\dfrac{\mathrm dy}{\mathrm dx}=xe^y
e^{-y}\,\mathrm dy=x\,\mathrm dx
-e^{-y}=\dfrac{x^2}2+C

y(0)=0
\implies-1=C
\implies -e^{-y}=\dfrac{x^2}2-1
e^{-y}=1-\dfrac{x^2}2
-y=\ln\left(1-\dfrac{x^2}2\right)
y=-\ln\left(1-\dfrac{x^2}2\right)
3 0
2 years ago
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